Answer:30km/hr
Step-by-step explanation:
Total distance=294km
Speed=s
Distance=d
Time=t
First drive:
t=5
d=s x t
d=s x 5
d=5s
Second drive:
t=4
Speed is 6km/h greater than the first speed
The new speed= s+6
d=4(s+6)
Total distance=294
5s + 4(s + 6)=294
5s + 4s + 24=294
Collect like terms
5s + 4s=294 - 24
9s=270
Divide both sides by 9
9s/9=270/9
s=30
First speed=30km/hr
Answer:
17
Step-by-step explanation:
Answer:
-15
Step-by-step explanation:
Answer:
12,400
Step-by-step explanation:
so what you are going to first is 400 times 31 which is 12,400
Answer:
There are two ways to do this problem algebraically or trigonometrically.
Algebraically/geometrically
The ratios of the sides of a 30/60/90 tri. are x, x√3, 2x (short leg, long leg, hyp). Therefore, if the long leg is 6 'units'. then 6 = x√3. x = 6√3.
The hyp is 2x then the hypotenuse is 2(6√3) = 12√3, rationalizing is 12√3/3 = 4√3
Using Trig.
We can use sinx = y/r = opp/hyp. The long leg of 6 is opposite 60 degrees (pi/3).
Therefore, sin(pi/3) = 6/r =
r = 6/sin(pi/3) = 6/(√3/2) = 12/√3, when you rationalize you get 12√3/3 = 4√3