Solution
The table below is the required sample space of the to fair die
From the above table
The sample space contain 36 outcomes
Event A: The sum is greater than 9
we will look at the table and count all the elements that are greater than 9
There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)
The probability for event A will be

P(A) = 1/6
Event B: The sum is an even number.
We will look at the table and count the number of elements that are even
There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)
The probability for event B will be

p(B) = 1/2
First 20 minutes:1 Second 20:2 Third 20:4 Fourth 20: 8. Fifth 20: 16 Sixth 20: 32. C is your answer
If the profit was 170 then 25 things were bought. since n is 25 you multiply it by 8 which is 200 and if you then subtract 30 the answer is 170
H(t) = t^(3/4) - 3t^(1/4)
The critical points can be evaluated by taking the first derivative and equating to 0.
h'(t) = 3 / t^(1/4) - 3 / 4t^(3/4)
3 / (4t^(3/4)) = 3 / t^(1/4)
4t^(3/4) = t^(1/4)
4 = 1/√t
t = 1/16, t = -1/16
I think the answer is ur dad