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ycow [4]
3 years ago
13

I. Collect data from several fast food chains on the number of fat calories and grams of saturated fat in menu items. Record at

least 12 ordered pairs of (fat calories, grams of saturated fat). Organize your data in a table.
II. Make a scatter plot of the data on graph paper. Be sure to label the axes and use an appropriate title for the graph.
You may wish to use a graphing calculator, spread sheet, or other technology resource (such as the graphing utility link below) to aid you in graphing.

Create a Graph
Mathematics
1 answer:
zhuklara [117]3 years ago
4 0

Where's the question?

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Consider the following argument. If there are as many rational numbers as there are irrational numbers, then the set of all irra
FrozenT [24]

Answer:

b. form: p → q invalid, converse error q ∴ p

Step-by-step explanation:

Let

p = "there are as many rational numbers as there are irrational numbers,"

let

q = "the set of all irrational numbers is infinite."

We can write the above argument as:

If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite

p → q

The set of all irrational numbers is infinite

q

There are as many rational numbers as there are irrational numbers

p

So collectively it can be written as:

p → q

 q

∴p

So it looks like

if p then q

q

therefore p

This is a fallacious argument.  This means the conclusion can be false even when the premises are true. This type of argument is invalid.

Suppose we know that “If there are as many rational numbers as there are irrational numbers, then the set of all irrational numbers is infinite” is a true conditional statement. We also know that "the set of all irrational numbers is infinite" is true. This is not enough to say that "there are as many rational numbers as there are irrational numbers," is true. The reason for this is that there is nothing logically about “If p then q” and “q” that means p must follow. So this is a converse error and since converse error is an invalid method of inference rule so this argument is invalid.

Let us prove this argument is invalid with a truth table:

p   q   p → q   q   p

T   T      T       T   T

T   F      F       F   T

F   T      T       T   F

F   F      T       F   F

Since we know that the premises are:

p → q   and  q

and the conclusion is p

and an argument is valid if and only if all of its premises are true, then the conclusion is true. We should check that whenever both p → q   and  q are true then p is true but the third row fails. Thus this is an invalid argument.

6 0
3 years ago
Street H is perpendicular to the line 2x –3y = –4 and goes (0, –6). Write this street’s equation in standard form.
storchak [24]

Answer:

I think its 68 + 1 = 69

Step-by-step explanation:

6 0
3 years ago
F(x) = -x - 3 Find f(-4) f(-4) = -(-4) -3
skelet666 [1.2K]

Answer:

\boxed{ \bold{ \boxed{ \sf{f( - 4) = 1}}}}

Step-by-step explanation:

Given, f ( x ) = - x - 3

Let's find the value of f ( - 4 )

\sf{f( - 4) =  - ( - 4) - 3}

We know that , ( - ) \times ( - ) = ( + )

⇒\sf{ 4 - 3}

Subtract 3 from 4

⇒\sf{1}

Hope I helped!

Best regards!!

5 0
3 years ago
Write an equation for the transformation of y = x.
Ivanshal [37]

Answer:

отлично вы молодец болшая у вас всё правилно

7 0
3 years ago
What is the value of x in the solution to the system of linear equations? {y=3x+2 y=x-4 a –7 b –3 c 1 d 5
lyudmila [28]

Since y must equal both 3x+2 and x-4, we deduce that 3x+2 and x-4 must equal each other. So, we have

3x+2=x-4 \iff 2x+2=-4 \iff 2x=-6 \iff x=-3

5 0
3 years ago
Read 2 more answers
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