Answer:
You did not post the options, but i will try to answer this in a general way.
Because we have two solutions, i know that we are talking about quadratic equations, of the form of:
0 = a*x^2 + b*x + c.
There are two easy ways to see if the solutions of this equation are real or not.
1) look at the graph, if the graph touches the x-axis, then we have real solutions (if the graph does not touch the x-axis, we have complex solutions).
2) look at the determinant.
The determinant of a quadratic equation is:
D = b^2 - 4*a*c.
if D > 0, we have two real solutions.
if D = 0, we have one real solution (or two real solutions that are equal)
if D < 0, we have two complex solutions.
Answer:
HCF=3
Step-by-step explanation:
Factors of 15t= 3*5*t
Factors of 6s= 2*3*s
HCF= Common factors
common factor = 3
HCF=3
Do you mean the last two? the 9 and 10 are cut off
Answer:
x = -4, -2
Step-by-step explanation:
-x² - 6x - 8 = 0
x² + 6x + 8 = 0
x² + 4x + 2x + 8 = 0
x(x + 4) + 2(x + 4) = 0
(x + 4)(x + 2) = 0
x = -4, -2
