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3 years ago

-3 > x - 13 who knows this question.

1 answer:

3 0

Solving inequality equations is pretty much the same as solving regular equations. What you do to one side, you have to do to both sides. Also, you are trying to get the variable(s) alone on one side of the inequality sign.

So, to solve, first you would add 13 to both sides to solidify the variable, resulting in the equation

10>x, which is your answer.

You might be interested in

AB, CD, and EF intersect at O. If CD is perpendicular to EF and m

REY [17]

Answer:

m(∠AOF) = 148°

Step-by-step explanation:

From the figure attached,

CD intersects line EF at a point O.

Line CD is perpendicular to the line EF.

m(∠AOE) = 32°

m(∠COE) = 90°

Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°

32° + m(∠AOC) = 90°

m(∠AOC) = 90° - 32° = 58°

m(∠AOF) = m(∠AOC) + m(∠COF)

= 58° + 90°

= 148°

Therefore, m(∠AOF) = 148° will be the answer.

4 0

3 years ago

It is 35,840 feet below sea level.is this about 36,000feet below sea level. explain

valentinak56 [21]

It is not about 36,000 because
about would be 3,600 or higher

6 0

3 years ago

Convert the polar equation to rectangular coordinates. (Use variables x and y as needed.)

Alinara [238K]

The standard conversion toolbox:
x=rcos(θ)
y=rsin(θ)

Here r=7csc(θ)
so
x=7csc(θ)*cos(θ)=7cos(θ)/sin(θ)=7cot(θ)
y=7csc(θ)*sin(θ)=7sin(θ)/sin(θ) = 7
therefore the rectangular coordinates are (7cot(θ), 7)

8 0

3 years ago

10 more than 2 times a number is equal to 2 times the number plus 50. What is the number?

PSYCHO15rus [73]

Answer:

y = 40 is the answer

Step-by-step explanation:

Let the number be y

10 more than 2 times a number = 10 + 2×y

equal to 2 times the number plus 50. = 2 × y + 50

10 + 2y = 2y + 50

combine the like terms

2y - 2y =50 - 10

0 = 40

the number supposes be 40 but the number is represented by 0

i think some thing is missing in your question

y supposes be 40 not 0 = 40

Hope this helps!

3 0

3 years ago

In right △ABC, the altitude CH to the hypotenuse AB intersects angle bisector AL in point D. Find the sides of △ABC if AD = 8 cm

tangare [24]

Answer:

$AC=8\sqrt{3}\ cm\\ \\AB=16\sqrt{3}\ cm\\ \\BC=24\ cm$

Step-by-step explanation:

Consider right triangle ADH ( it is right triangle, because CH is the altitude). In this triangle, the hypotenuse AD = 8 cm and the leg DH = 4 cm. If the leg is half of the hypotenuse, then the opposite to this leg angle is equal to 30°.

By the Pythagorean theorem,

$AD^2=AH^2+DH^2\\ \\8^2=AH^2+4^2\\ \\AH^2=64-16=48\\ \\AH=\sqrt{48}=4\sqrt{3}\ cm$

AL is angle A bisector, then angle A is 60°. Use the angle's bisector property:

$\dfrac{CA}{CD}=\dfrac{AH}{HD}\\ \\\dfrac{CA}{CD}=\dfrac{4\sqrt{3}}{4}=\sqrt{3}\Rightarrow CA=\sqrt{3}CD$

Consider right triangle CAH.By the Pythagorean theorem,

$CA^2=CH^2+AH^2\\ \\(\sqrt{3}CD)^2=(CD+4)^2+(4\sqrt{3})^2\\ \\3CD^2=CD^2+8CD+16+48\\ \\2CD^2-8CD-64=0\\ \\CD^2-4CD-32=0\\ \\D=(-4)^2-4\cdot 1\cdot (-32)=16+128=144\\ \\CD_{1,2}=\dfrac{-(-4)\pm\sqrt{144}}{2\cdot 1}=\dfrac{4\pm 12}{2}=-4,\ 8$

The length cannot be negative, so CD=8 cm and

$CA=\sqrt{3}CD=8\sqrt{3}\ cm$

In right triangle ABC, angle B = 90° - 60° = 30°, leg AC is opposite to 30°, and the hypotenuse AB is twice the leg AC. Hence,

$AB=2CA=16\sqrt{3}\ cm$

By the Pythagorean theorem,

$BC^2=AB^2-AC^2\\ \\BC^2=(16\sqrt{3})^2-(8\sqrt{3})^2=256\cdot 3-64\cdot 3=576\\ \\BC=24\ cm$

3 0

2 years ago