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yuradex [85]
3 years ago
10

The distances (y), in miles, of two cars from their starting points at certain times (x), in hours, are shown by the equations b

elow:
Car A
y = 45x + 20

Car B
y = 35x + 60

After how many hours will the two cars be at the same distance from their starting point and what will that distance be?

3 hours, 200 miles

3 hours, 180 miles

4 hours, 200 miles

4 hours, 180 miles
Mathematics
1 answer:
Brrunno [24]3 years ago
6 0
Use the "y=mx+b" formula to solve your answer
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Factor completely: x^2-y^2-1.5(x-y)
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Step-by-step explanation:

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If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.
Lelechka [254]

Answer:

\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)

So we can say that

a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab

and we can notice that

a^2+b^2=(a+b)^2-2ab so

(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab

it comes

x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}

multiply by 3

3x^2-20x+2*16+5=3x^2-20x+37

4 0
3 years ago
I need help I'm not so good with geometry
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What's C and A mean?
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