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leva [86]
3 years ago
9

A football is passed through the air and caught at ground level for a touchdown. The height of the ball (h) is given by h= -d² +

12d + 6, where d is the distance in feet the ball travels horizontally. How far from the player passing the ball will the ball be caught?
40 Points! Will mark Brainliest!
Mathematics
1 answer:
IgorC [24]3 years ago
3 0

Answer:

d = 6+sqrt(42)=12.4807407

Step-by-step explanation:

h= -d² + 12d + 6

The ball is caught at ground level  which means h=0

0 =  -d² + 12d + 6

Subtract 6 from each side

-6 = -d^2 +12d

Factor out a - sign

-6 =-(d^2-12d)

Divide by -1

6 = d^2 -12 d

Complete the square

-12/2 = -6  then square it = 36

Add 36 to each side

6+36 = d^2 -12d +36

42 = (d-6)^2

Take the square root of each side

±sqrt(42) = sqrt( (d-6)^2)

±sqrt(42) =  (d-6)

Add 6 to each side

6±sqrt(42) =  (d-6)+6

6±sqrt(42) =  d

d = 6+sqrt(42)=12.4807407

d =6- sqrt(42)=-.480740698

Since the distance cannot be negative

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4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%201%20%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B7x%20-%203%7D%7B2%7D%20" id="Tex
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\sf x =\dfrac{2}{3}

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\sf \rightarrow \dfrac{x+1}{2} = \dfrac{7x-3}{2}

cross multiply

\sf \rightarrow 2(x+1) = 2(7x-3)

divide both sides by 2

\sf \rightarrow x + 1 = 7x-3

isolate variables

\sf \rightarrow x -7x = -3-1

simplify

\sf \rightarrow -6x = -4

divide both sides by -6

\sf \rightarrow \dfrac{-6x}{-6}  = \dfrac{-4}{-6}

simplify

\sf \rightarrow x =\dfrac{2}{3}

4 0
1 year ago
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