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sdas [7]
4 years ago
11

How do I work out the following simultaneous equations?

Mathematics
1 answer:
Sveta_85 [38]4 years ago
7 0
I'll show you two ways.

By substitution:

x+3y=11\\
2x-y=1\\\\
x=11-3y\\
2x-y=1\\\\
2(11-3y)-y=1\\
22-6y-y=1\\
-7y=-21\\
y=3\\\\
x=11-3\cdot3\\
x=11-9\\
x=2\\\\
\boxed{(x,y)=\left(2,3\right)}

By elimination:

x+3y=11\\ 2x-y=1|\cdot 3\\\\
x+3y=11\\
\underline{6x-3y=3}\\
7x=14\\
x=2\\\\ 2+3y=11\\
3y=9\\ y=3\\\\
\boxed{(x,y)=\left(2,3\right)}
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Give the inequality -8<2 explain what happens when you multiply or divide both sides by 2 and what happens when you multiply
rodikova [14]

Answer:

If we multiply both the sides by 2, the inequality signs remains the same.

If we divide both sides by -2, the sign changes.

Step-by-step explanation:

The given inequality is

-8<2

If we multiply both the sides by 2, we get

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The inequality signs remains the same.

On the other hand if we divide both sides by -2, we get -

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Here the sign changes.

4 0
3 years ago
Which expression is equivalent to five to the tenth power multiplied by five to the fifth
ioda

Answer:

30517578125

Step-by-step explanation:

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Lemur [1.5K]
Answer:
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Explanation:
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1. A local pizzeria sold 70 pizzas yesterday.
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Answer:

1. 91 = 70*1.30

2a. 195= 150*1.30

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3b.  132.30 = 156-56.70

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3e. You do not have enough money, because you need $9.50 more.

Step-by-step explanation:

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