The flow of energy from one level to another does not happen with 100% efficiency. The producers only transfer 10% of the energy they absorb from the Sun. The major chunk of the absorbed energy goes into the growth of the producers, the rest gets lost in the form of waste (shedding of leaves, reproduction, etc.) and the remaining 10% is the amount that is available to the primary consumers. So by this logic, if there is 150,000 KJ of energy available at the producer level, then, only 15,000 KJ of energy will get transferred to the primary consumers.
Answer:
362 nucleosomes
Explanation:
A nucleosome repeat is made up of the DNA (146 bp) wrapped around the core nucleosome particle and the linker DNA (110 bp as in this situation). We can conclude that, every repeat stands for 256 (146 + 110) base pairs of DNA.
We are given the length of the entire region to be 92,672 bp long,
To determine the number of nucleosomes to organize the region into the 10nm fiber structure
Let,
Number of nucleosomes =
the length of the entire region
------------------- -----
base pairs of DNA.
= 92,672
-------
256
= 362 nucleosomes
Therefore, 362 nucleosomes is needed to structure the region into the 10nm fiber structure.
There are many factors that contribute to the growth of a plant . Like what type of light is used and it also depends on the type of plant it is but in this context, your answer is A
Answer:
A). glucose
D). carbon dioxide
E). energy
Explanation:
Aerobic Respiration is characterized as the respiration process(metabolic reaction or breaking down of glucose into energy) that occurs in presence of oxygen while anaerobic respiration takes place in the absence of oxygen. The things that are common in both include glucose, energy, and carbon dioxide. <u>Glucose is broken down in both processes(with or without oxygen) while energy and CO2 are the byproducts/released products of the process</u>. Thus, <u>options A, D, and E</u> are the correct answers.
The answer is: The reaction rate of the forward reaction would increase in order to decrease the number of particles. (B)
