I believe that the answer is C because lets say you decide that the cube will roll on 1 six times. if you roll the cube 6 times, then there is a 1/6 probability of the cube landing on 1, but the more times you roll the cube, the more chances there will be of the number landing that many times as you theorized
Answer:
The 1st error that Carlos made was in Step 2...
In step 2 , Carlos multiplied 14 only with 40. If he would have multiplied 14 with both 40 & 9 , then it could have been alright.....
The coefficient of determination is the square of the correlation coefficient, and the value is 0.0151
<h3>How to determine the coefficient of determination?</h3>
The given parameter is:
Correlation coefficient, r = 0.123
Rewrite as:
r = 0.123
Take the square of both sides
r² = 0.123²
Evaluate the square
r² = 0.015129
Approximate
r² = 0.0151
The coefficient of determination is represented by r²
Hence, the coefficient of determination is 0.0151
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since it has a diameter of 28, then its radius must be half that or 14.
![\textit{area of a circle}\\\\ A=\pi r^2~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=14 \end{cases}\implies A=\pi (14)^2\implies A=196\pi ~\hfill \stackrel{\stackrel{semi-circle}{half~that}}{98\pi }](https://tex.z-dn.net/?f=%5Ctextit%7Barea%20of%20a%20circle%7D%5C%5C%5C%5C%20A%3D%5Cpi%20r%5E2~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D14%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Cpi%20%2814%29%5E2%5Cimplies%20A%3D196%5Cpi%20~%5Chfill%20%5Cstackrel%7B%5Cstackrel%7Bsemi-circle%7D%7Bhalf~that%7D%7D%7B98%5Cpi%20%7D)
Answer:3000m and 3km
Step-by-step explanation:
To convert from cm to m,divide by 100 and from m to km,divide by 1000