Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .
<u>Step-by-step explanation:</u>
Here we have , Leanne runs a lap in 12 minutes. Kory runs a lap in 9 minutes. We need to find out that If they both start running at 10 am, at what time will they both cross the start together again . Let's find out:
Kory runs a lap in 9 minutes and , Leanne in 12 minutes , in order to find at what time will they both cross the start together again we will find LCM of 9 & 12 :
⇒ 
⇒ 
So ,LCM of 9 & 12 is 36 .That means Kory and Leanne will meet each other again after 36 minutes from starting i.e. at 10:36 am .
In clear way , Kory will run race as :
1st lap = 9 minutes
2nd lap = 18 minutes
3rd lap = 27 minutes
4th lap = 36 minutes , i.e. at 10:36 am he'll complete his 4th lap
For , Leanne
1st lap = 12 minutes
2nd lap = 24 minutes
3rd lap = 36 minutes i.e. at 10:36 am he'll complete his 3rd lap .
This means Kory & Leanne will meet at 10:36 am completing there 4th and 3rd lap respectively .
K I think that it is okay because it would be 10
Answer:
C = 35 + 45h
In the equation above $35 is the initial value which interprets the cost for motor parts and $45/hour is the rate of charge of the mechanic per hour.
Step-by-step explanation:
Charges for parts and $45 per hour for labor that takes a mechanic for maintenance of a car.
It costs $125 as Terri spent 2 hours for car maintenance.
Since the function is linear, so we can write
125 = 45 × 2 + x {Where x is the charges for parts}
⇒ x = 35
Therefore, the equation that models the situation is given by
C = 35 + 45h ......... (1)
where C is the total cost and h is the number of hours.
Here, in equation (1) $35 is the initial value that interprets the cost for parts and $45/hour is the rate of charge of the mechanic per hour. (Answer)
Answer:
13620
Step-by-step explanation:
you just need to multiply 1135 by 12
The width of a rectangular room is 3 m shorter than its length. If its perimeter must not exceed 42 m, calculate the greatest length that the room can have.