Please help me answer this question!!! and explain bc im very stupid and my grades are low. 15 points

Mathematics

1 answer:

mariarad [96]4 years ago

6 0

Answer:

Step-by-step explanation:

The top angle is 90 degrees, so I would assume that m<1 is 90 degrees. Plugging this into the equation gives us 90 = 4y + 22. Subtract 22 from both sides, and we get 68 = 4y. Divide both sides by 4, and we get 17 = y.

You might be interested in

What is the arc length when theta=pie/3 and the radius is 5 cm

Jobisdone [24]

Answer:

Hey There!

Let's solve....

Radius=5cm

Angle = pi/3

Therefore arc length= Radius×angle

$= 5 \times \frac{\pi}{3} \\ \\ let \: \pi \: be \: 3.14cm \: so \: \\ \\ 5 \times \frac{3.14}{3} \\ \\ = \frac{15.70}{3} \\ \\ = 5.23cm$

The arc length is 5.23 cm when Theta=pi/ 3 and radius is 5 cm.

<h2>I hope it is helpful to you...</h2><h3>Cheers!_________</h3>

5 0

2 years ago

The digit 5 appears twice in the number 255,120. How does the total value of the 5 on the right compare to the total value of th

maksim [4K]

Answer:

The value of the first " $5$ " in the number $255,\!120$ is ten times that of the second " $5\!$ " in this number.

Step-by-step explanation:

What gives the number " $255,\!120$ " its value? Of course, each of its six digits has contributed. However, their significance are not exactly the same. For example, changing the first $\verb!5!$ to $\verb!6!$ would give $2\mathbf{6}5,\!120$ and increase the value of this number by $10,\!000$ . On the other hand, changing the second $\verb!5!\!$ to $\verb!6!\!$ would give $25\mathbf{6},\!120$ , which is an increase of only $1,\!000$ compared to the original number.

The order of these two digits matter because the number " $255,\!120$ " is written using positional notation. In this notation, the position of each digits gives the digit a unique weight. For example, in $255,\!120\!$ :

$\begin{array}{|r||c|c|c|c|c|c|}\cline{1-7}\verb!Digit!& \verb!2! & \verb!5! & \verb!5! & \verb!1! & \verb!2! & \verb!0!\\\cline{1-7}\textsf{Index} & 5 & 4 & 3 & 2 & 1& 0 \\ \cline{1-7} \textsf{Weight} & 10^{5} & 10^{4} & 10^{3} & 10^{2} & 10^{1} & 10^{0}\\\cline{1-7}\end{array}$ .

(Note that the index starts at $0$ from the right-hand side.)

Using these weights, the value $255,\!120$ can be written as the sum:

$\begin{aligned}& 255,\!120\\ &= 2 \times 10^{5} + 5 \times 10^{4} + 5 \times 10^{3} + 1 \times 10^{2} + 2 \times 10^{1} + 0 \times 10^{0} \\&=200,\!000 + 50,\!000 + 5,\!000 + 100 + 20 + 0 \end{aligned}$ .