I'm going to assume that you mean't mole instead of mile. One mole of O2 has approximately the same mass of one "mole" of N2. I say this because if these elements were rounded by their atomic mass, N would stay as 14, O would round up to 16, and we wouldn't; in this case, O2 would have approximately the same mass as F because F rounds up to 19 and the different between O and N is only 2 while the difference between O and F is 3.
Answer:
CH3OH
Explanation:
As it lacks

electrons hence it will not exist as resonance hybrid.
Answer:
C2H4
Explanation:
The image attached shows a detailed solution of the above problem. The empirical formula shows the ratio of the atoms of each element present.