1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Solnce55 [7]
4 years ago
6

Find the average atomic mass of the element, given the isotopic percentage of 75.0% for cl35 and 25.0% for cl-37.

Chemistry
1 answer:
Mandarinka [93]4 years ago
5 0

The  average atomic mass of the element = 35.5


calculation

average atomic mass =  sum of the masses of its isotope each multiplied by its natural abundance.

that is

[(75 x35) +(25 x37)] /100 = 35.5

You might be interested in
Acids, bases, and salts belong to a large group of compounds called:__________
astraxan [27]

Answer:

electrolytes

Explanation:

6 0
2 years ago
Click the DeltaH is an Extensive Property button within the activity, and analyze the relationship between the two reactions tha
DaniilM [7]

Answer:

∴ΔH₂ = - 12,258 KJ

Explanation:

Enthalpy:

Enthalpy is a property of a thermodynamic system. Enthalpy of a system is equal to the sum of internal energy of the system and presser times volume of the system.

    The heat absorbes or releases in a closed system is the change of enthalpy of the system.

Given reactions are:

Reaction 1: C₃H₈(g)+5O₂(g)→ 3CO₂(g)+4H₂O,                 ΔH₁= - 2043 KJ

Reaction 2: 6C₃H₈(g)+30 O₂(g)→ 18 CO₂(g)+24 H₂O,     ΔH₂=?

Take a look at reaction 1 and reaction 2, the only difference is that 1 molecule of C₃H₈ is combusted in reaction 1 and 6 molecules of C₃H₈  is  combusted in reaction 2.

We can think the reaction 2 as occurring 6 different container and each containers contains 1 molecule of C₃H₈. The enthalpy is an extensive property. Total enthapy of the 6 containers is = 6×(-2043 KJ)

                                                                            = - 12,258 KJ

∴ΔH₂ = - 12,258 KJ

6 0
4 years ago
what is the empirical formula of vanadium 1 oxide given that 20.38 grams of vandium combines with oxygen to form 23.58 grams of
Alex

Answer:

The empirical formula is V₂O

Empirical formula of a compound is the formula that shows the simplest whole number ratio of the atoms of elements in a given compound. Empirical formula is normally calculated when the mass of each element in a compound is known or the percentage composition by mass of each element in a compound is known.

Step by Step Explanation:

Step 1: Percentage composition of each element

Percentage composition=(mass of an element/ mass of the compound)100%

Mass of Vanadium = 20.38 g

Mass of the compound = 23.58 g

% composition of Vanadium = (20.38 g/23.58 g) 100%

                                                 = 86.43 %

Mass of Oxygen = 23.58 g -20.38 g

                           = 3.2 g

% composition of oxygen = (3.2/g/23.58 g) 100%

                                          =  13.57%

Step 2: Find the number of atoms of each element in the compound

Number of atoms  = percentage composition/ atomic mass

Atomic mass of Vanadium = 50.94 g/mol

Number of atoms of V = 86.43 /50.94

                                  = 1.6967

Atomic mass of oxygen = 16 g/mol

Number of atoms of O = 13.57/16

                                      = 0.8481

Step 3:  Find the simplest ratio of atoms

Vanadium : Oxygen

            1.6967 : 0.8481

= 1.6967/0.8481 : 0.8481/0.8481

= 2: 1

Whole number ratio = 2 : 1

Therefore; the empirical formula is V₂O

8 0
3 years ago
Read 2 more answers
For an organism’s scientific names, the first part is the ________ and the second is the ________.
kari74 [83]

Answer:

C

Explanation:

For an organism scientific names the first part is the genus and the second is the species

3 0
3 years ago
Read 2 more answers
Refer to the two formulas for xylose.
Ludmilka [50]

Answer:

A is the molecular formula for xylose because shows the actual number of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the molecular formula for xylose because shows the arrangement of atoms in the compound: Formula B is the structurab formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the empirical formula for xylose because it shows the actual number of atoms in the compound: Formula B is the molecular formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the structural formula for xylose because it shows the arrangement of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound.

5 0
3 years ago
Other questions:
  • Examples of chemical changes in nature
    9·2 answers
  • The process of transporting rock material is called
    7·1 answer
  • Consider the molecule SiCl4. The electronegativity values for Si and Cl are 1.8 and 3.0, respectively. Based on these values and
    6·2 answers
  • What can you say about density if volume increase and mass stays the same
    9·2 answers
  • How many kPa are in 924.8 torr?
    9·1 answer
  • Which term refers to the sum of the kinetic energy of all the particles in an object? O A. Heat O B. Potential energy O C. Therm
    11·1 answer
  • Choose all the right answers.
    9·2 answers
  • Explain what is happening to molecules in the chemical reaction shown here. Helpful vocabulary: the
    11·1 answer
  • Which of these electron transitions correspond to absorption of energy and which to emission?
    12·1 answer
  • Determine the volume occupied by the following amounts of nitrous oxide, N₂O(g),
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!