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sleet_krkn [62]
3 years ago
15

Which of the following would not cause an increase in the pressure inside a sealed container of neon gas?

Chemistry
2 answers:
MrRissso [65]3 years ago
5 0

Hey there! Your answer is C. Increasing the volume of the container

This is because the container is already sealed, so the volume is fixed.

r-ruslan [8.4K]3 years ago
3 0

The pressure in a sealed container means the volume of container is fixed

so we cannot change the volume of container hence gas

The other factors which can affect the pressure are

a) moles of gas : if we increase the moles of gas the pressure of gas will increase

b) Temperature: if we increase the pressure of gas the pressure of gas will increase due to increase in kinetic energy

So the following cannot increase pressure

a) decrease in moles of gas

b) decrease in temperature of gas

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URGENTTTTT HELPPPP PLZZZ LAST TRYYY
algol13

Left Panel

A is an acid. Not the answer.

B is correct. That would be a base. But it is not an Arrhenius base. Keep reading.

C that is exactly what an Arrhenius base is.

D. No an acid of some sort would accept OH ions.

Right Panel

D is concentrated and it is also a weak base. Good cleaning fluid. Smells awful but it works.

8 0
3 years ago
How many grams of sucrose (C12H22O11) would be in 8.7 L of a 6.81M solution of sucrose
VladimirAG [237]
<h3><u>Answer;</u></h3>

= 20,280.25 g or 20.28 Kg

<h3><u>Explanation;</u></h3>

Number of moles, n = Molarity × Volume

Molarity = 6.81 M

Volume = 8.7 L

Number of moles = 6.81 × 8.7

                             = 59.247 moles

Mass = Moles × Molar mass

         = 59.247 ×  34.2 g/mol

          = 20,280.25 or

          = 20.28 Kg

7 0
3 years ago
1.00 g of a compound is combusted in oxygen and found to give 3.14g of CO2 and 1.29 g of H2O. From these data we can tell thatA.
lora16 [44]

Answer:

the compound contains C, H, and some other element of unknownidentity, so we can’t calculate the empirical formula

Explanation:

Mass of CO2 obtained = 3.14 g

Hence number of moles of CO2 = 3.14g/44.0 g = 0.0714 mol

The mass of the carbon in the sample = 0.0714 mol × 12.0g/mol = 0.857 g

Mass of H2O obtained = 1.29 g

Hence number of moles of H2O = 1.29g/18.0 g = 0.0717 mol

The mass of the carbon in the sample = 0.0717 mol × 1g/mol = 0.0717 g

% by mass of carbon = 0.857/1 ×100 = 85.7 %

% by mass of hydrogen = 0.0717/1 × 100 = 7.17%

Mass of carbon and hydrogen = 85.7 + 7.17 = 92.87 %

Hence, there must be an unidentified element that accounts for (100 - 92.87) = 7.13% of the compound.

5 0
3 years ago
Help please I need help with these two questions answer truthfully get brainliest?!!​
irina1246 [14]

Answer:

1. 3x-3=18

Value of x=7

2. 4x-5=23

value of x=7

5 0
3 years ago
Read 2 more answers
The most common form of energy encountered in chemical reactions is _____. Select one:
Svetllana [295]
The answer is b heat
3 0
3 years ago
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