Answer:
21 and 26 totaling 47sticks
Step-by-step explanation:
Th number of sticks form an arithmetic progression
1, 6, 11, 16...
The nth term of an arithmetic progression is expressed as;
Tn = a+(n-1)d
a is the first term = 1
d is the common difference
d = 6-1 = 11-6 = 5
n is the number of terms
The next two terms are the fifth and sixth term
T5 = 1+(5-1)5
T5 = 1+4(5)
T5 = 1+20
T5 = 21
T6 = 1+(6-1)5
T6 = 1+5(5)
T6 = 1+25
T6 = 26
Hence the number of sticks needed in the next two piles are 21 and 26 totaling 47sticks
Answer:
Step-by-step explanation:
Answer:
49.0
Step-by-step explanation:
9514 1404 393
Answer:
16
Step-by-step explanation:
48 = 16·3
112 = 16·7
80 = 16·5
3, 5, 7 have no common factors. The GCF of {48, 112, 80} is 16.
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It can be helpful to recognize 48 = 16·3 and 80 = 16·5. A simple check shows 112 = 16·7, so 16 is the GCF.
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You can find GCF(48,112) using Euclid's algorithm:
112 mod 48 = 16
48 mod 16 = 0 ⇒ GCF(48, 112) = 16
and the GCF(16, 80) is ...
80 mod 16 = 0 ⇒ GCF(16, 80) = 16
So, GCF(48, 80, 112) is 16.
Answer:
1/10
Step-by-step explanation:
1 minus 9/10 is 1/10
