If nuts cost $9.20 per pound, how much would 2 1/2 pound cost?

Select all the expressions that are equivalent to 9 + 7x – 3y. 9 + 7x + 3y 9 – 7x – 3y 9 – 7x + 3y 9 + 7x + (–3y) 9 – (–7)x – 3y

bulgar [2K]

0^9 +7x+189yx−3y

o

9

+7x−3y

9

+7x+3y

9

−7x−3y

9

−7x+3y

9

+7x+189yx−3y

2 Collect like terms.

{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y

o

9

+(7x+7x−7x−7x+7x)+(−3y

9

+3y

9

−3y

9

+3y

9

)+189yx−3y

3 Simplify.

{o}^{9}+7x+189yx-3y

o

9

+7x+189yx−3y

6 0

3 years ago

Find The distance between (-3,1) and (-1,6). If necessary,round to the nearest tenth.

kifflom [539]

Use distance formula:-

distance = sqrt [ (x2 - x1)^2 + (y2 - y1)^2) ]

let (x1,y1) = (-3,1) and (x2,y2) = (-1,6) Plug these values in to formula.

8 0

3 years ago

There are nickels, dimes, quarters in a large piggy bank, for every 2 nickels there are 3 dimes, for every 2 dimes there are 5 q

Alex

There are 80 nickels and 120 dimes and 300 quarters in piggy bank

<em><u>Solution:</u></em>

Given that,

For every 2 nickels there are 3 dimes ,

So, ratio of nickel to dime will be 2 : 3

Also for every 2 dimes there are 5 quarters

So, ratio of dime to quarters is 2 : 5

Let us first find the ratio of nickles to dimes to quarters

nickel : dime = 2 : 3

dime : quarters = 2 : 5

$\frac{nickel}{dime} = \frac{2}{3}$

$nickel = \frac{2}{3} dime$

$\frac{dime}{quarter} = \frac{2}{5}$

$quarter = \frac{5}{2}dime$

So,

$nickel : dime : quarter = \frac{2}{3}dime : dime : \frac{5}{2}dime\\\\nickel : dime : quarter = \frac{2}{3} : 1 : \frac{5}{2}\\\\nickel : dime : quarter = 4 : 6 : 15$

Thus nickel : dime : quarters = 4 : 6 : 15

Now, let the number of nickel be 4x

Let the number of dimes be 6x

Let the number of quarters be 15x

From given question,

There are 500 coins in all.

number of nickel + number of dimes + number of quarters = 500

4x + 6x + 15x = 500

25x = 500

x = 20

Thus,

number of nickel = 4x = 4(20) = 80

number of dimes = 6x = 6(20) = 120

number of quarters = 15x = 15(20) = 300

Thus there are 80 nickels and 120 dimes and 300 quarters in piggy bank

3 0

3 years ago

(3x-4y)^2-(3x-4y)(3x+4y)

zheka24 [161]

Answer:

$-24xy + 32y^2$

Step-by-step explanation:

Hello!

We can use the special binomial product formulas:

$(a + b)^2 = a^2 + 2ab + b^2$
$(a + b)(a - b) = a^2 - b^2$

<h3>Simplify</h3>

$(3x - 4y)^2 - (3x - 4y)(3x + 4y)$
$(9x^2-24xy+16y^2) - (9x^2 - 16y^2)$
$9x^2 - 9x^2 - 24xy + 16y^2 + 16y^2$
$-24xy + 32y^2$

The simplified form is $-24xy + 32y^2$

6 0

2 years ago

Emma is making a recipe that needs 2 1/2 cups of sugar. Each

IrinaVladis [17]

The given partial fraction divided by the fraction of sugar in a scoop is

equal to multiplying the partial fraction by the reciprocal of the fraction.

The number of scoops of sugar needed is <u>10 scoops</u>.

Reasons:

The amount of sugar the recipe Emma is making needs = 2 1/2 cups

Amount of sugar in each scoop of sugar = 1/4 cups

Required:

The amount of scoops Emma needs to add for the entire recipe

Solution:

The amount of sugar needed = 2 1/2 cups

Amount of sugar per scoop = 1/4 cups/scoop

Therefore;

$\displaystyle Number \ of \ scoops = \mathbf{\frac{Cups \ of \ sugar \ needed}{Cups \ of \ of \ sugar \ per \ scoop}}$

Which gives;

$\displaystyle Number \ of \ scoops \ needed = \mathbf{\frac{2 \frac{1}{2} \ cups \ of \ sugar }{\frac{1}{4} \ cups \ of \ sugar \ per \ scoop}}$

$\displaystyle 2 \frac{1}{2} = \frac{5}{2}$

$\displaystyle \frac{ \frac{5}{2}}{\frac{1}{4} } = \mathbf{ \frac{5}{2} \times \frac{4}{1} = \frac{20}{2 }} = 10$

Therefore;

$\displaystyle Number \ of \ scoops \ needed = \mathbf{\frac{2 \frac{1}{2} \ cups \ of \ sugar }{\frac{1}{4} \ cups \ of \ sugar \ per \ scoop}} = 10 \, scoops$

The number of scoops she needs for the entire recipe is <u>10 scoops</u>

Learn more about division by fractions here:

brainly.com/question/20591763

3 0

3 years ago