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bixtya [17]
3 years ago
8

Lucy has a coin collection of quarters from different states.The value of her collection is $9.50.How many quarters does she hav

e in her collection and what is the equation for this problem
Mathematics
2 answers:
marta [7]3 years ago
4 0

Answer:

38

Step-by-step explanation:

4 quarters in a dollar

4x9=36+2=38

Leona [35]3 years ago
3 0

Answer:

38 quarters

Step-by-step explanation:

write a equation for the word problem

0.25x=9.50

1 quarter: 25 cent

now you divided both sides by 0.25

0.25x/0.25 = 9.50/0.25

x= 38

Answer check:

substitute (x) for 38 to if your answer is right

0.25(38)= 9.50

9.5= 9.50

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3 years ago
I need to know this asap!
Vinvika [58]

w+2x=16 ⇒ w=16-2x


x+2w=14        x+2(16-2x)=14

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                     -3x=14-32

                      -3x=-18  /:(-3)

                       x=6


w=16-2x=16-2·6=16-12=4


2y+w=-6 ⇒   2y+4=-6

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4 0
3 years ago
An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
What is the slope of this ?
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Answer:

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1. Stick to the more visual aspect of it, and count how many units up from one point to the next point. Point (1,2) is 2 units up from point (0,0). Then you count how many units right or left it goes. In this case, it's 1 towards the right. This means the rise/run comes out to be 2/1, which means the slope=2.

2. Look at the equations. y=mx+b is the linear format for these lines. y is the y coordinate, m is the slope, x is the x coordinate, and b is the y intercept (the point where x=0). These two lines have shared slope values, which means the slope for both of them is 2.

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Answer:

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