Valerie and Robbie are playing a number game.

Problem 4:

Kipish [7]

Answer:

12cm and 16cm

Step-by-step explanation:

The hypotenuse of the right angle triangle = 20cm

let the other two sides be x and y;

The difference;

x = y - 4

Problem:

Find x and y;

Solution:

According to the pythagoras theorem;

x² + y² = 20² ------ i

x² + y² = 400 ----- i

and x - y = 4 ---- ii

So; x = 4 + y

Now input the value into equation (i);

(y + 4)² + y² = 400

(y+4)(y+4) + y² = 400

y² + y² + 4y + 4y + 16 = 400

2y² + 8y + 16 = 400

2y² + 8y + 16 -400 = 0

2y² + 8y - 384 = 0;

y² + 4y - 192 = 0

Factorize the equation;

y² + 16y - 12y - 192 = 0

y(y + 16) - 12(y + 16) = 0

(y-12)(y + 16) = 0

y -12 = 0 or y+ 16 = 0

y = 12 or -16

It is not realistic for the length of a body to be a negative value, so y= 12;

since;

x - y = 4,

x = 4 + 12

x = 16

5 0

3 years ago

What is the triangle's base, b?

Oksi-84 [34.3K]

Answer:

6.928 or 6.93

Step-by-step explanation:

\sqrt{8^{2}-4^{2}}

4 0

2 years ago

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If someone can answer this and explain it, I would really appreciate it, thanks.

daser333 [38]

Answer:

x = 13

Step-by-step explanation:

Now since the lines are parrarel, the intersection points are alternate to each other. Therefore, A = B.

Solve:

8x + 2 = 14x - 76

2 + 76 = 6x

78 = 6x

x = 13

8 0

2 years ago

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The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

2 years ago

What is the vertex of the graph of y + 2x + 3 = –(x + 2)2 + 1? (–3, –33) (–3, 3) (3, –24) (3, 21)

Arte-miy333 [17]

ANSWER

(-3,3)

EXPLANATION

The given function is

$y + 2x + 3 = - (x + 2) ^{2} + 1$

Expand

$y + 2x + 3 = - x ^{2} - 4x - 4 + 1$

Rewrite in the form:

$y =a {x}^{2} + bx + c$

This implies that,

$y = - x ^{2} - 4x - 2 x - 4 + 1 - 3$

$y = - {x}^{2} - 6x - 6$

Complete the square to get,

$y = - ( {x}^{2} + 6x) - 6$

$y = - ( {x}^{2} + 6x + {(3)}^{2} ) - - {(3)}^{2} - 6$

$y = - {(x + 3)}^{2} +9 - 6$

$y = - {(x + 3)}^{2} +3$

The function is now in the form:

$y = a {(x - h)}^{2} +k$

where (h,k) =(-3,3) is the vertex

8 0

3 years ago

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