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3 years ago

Fin the values of x and y, help me

Mathematics

1 answer:

astraxan [27]3 years ago

3 0

Answer:

x = 25 , y = 19

Step-by-step explanation:

Since the triangle has 3 congruent sides then it is equilateral

The 3 angles are also congruent, with each angle = 60° , then

2x + 10 = 60 ( subtract 10 from both sides )

2x = 50 ( divide both sides by 2 )

x = 25

and

3y + 3 = 60 ( subtract 3 from both sides )

3y = 57 ( divide both sides by 3 )

y = 19

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Given the function f(3) = 36 complete the following table

frozen [14]

Okay so here we have the function f(x)=3x-6 if you plug in -2 to x you get -12 if you plug in -1 you get -9 and if you plug in 0 you get -6 add three each time

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2 years ago

In Youngtown, the population reached 4420 people in 1993. In 1998, there were 5600 residents. What was the population in the yea

Ede4ka [16]

Growth rate = (Present - Past)/Past Plugging in what we know Growth rate =(5600â’4420)/4420 Thus Growth rate=.26697 Now we can plug the growth rate into our first formula which gives us P=5600e^(.26697â‹…2) Solve for P and we get P = 9551.58 however since you can not have .58 of a person we round down to 9551. So Youngtown will have 9551 citizens in the year 2000

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3 years ago

G wants to get over 9000 comments on his videos. He gets the same number of comments for each cat video that he uploads, and he

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4 0

1 year ago

Read 2 more answers

GI and JL are parallel lines. Which angles are supplementary angles?

solmaris [256]

Answer:

The answer is A.

Step-by-step explanation:

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2 years ago

A simple random sample of size n equals 200 individuals who are currently employed is asked if they work at home at least once p

____ [38]

Answer: 99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

Step-by-step explanation:

step 1:-

Given sample size n=200

of the 200 employed individuals surveyed 41 responded that they did work at home at least once per week

Population proportion of employed individuals who work at home at least once per week P = $\frac{x}{n} =\frac{41}{200} =0.205$

Q=1-P= 1-0.205 = 0.705

step 2:-

Now $\sqrt{\frac{P Q}{n} } =\sqrt{\frac{(0.205)(0.705)}{200} }$

=0.0015

step 3:-

Confidence intervals

using formula

$(P - Z_∝} \sqrt{\frac{P Q}{n},} (P + Z_∝} \sqrt{\frac{P Q}{n},$

$(0.205-2.58(0.0015),0.205+2.58(0.0015)\\0.20113,0.20887$

=0.20113,0.20887[/tex]

conclusion:-

99% of confidence interval for the population proportion of employed individuals who work at home at-least once per week

//0.20113,0.20887[/tex]

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3 years ago