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Citrus2011 [14]
2 years ago
8

What is the lateral area of the pyramid

Mathematics
1 answer:
Mkey [24]2 years ago
3 0

Answer:

43.75 ft²

Step-by-step explanation:

s_l = (l√(w/2)² + h²) + (w√(l/2)² + h²)

l & w become 3.5, and h becomes 6.

<em />s_l<em> </em>= (3.5√(3.5/2)² + 6²) + (3.5√(3.5/2)² + 6²)

<em>Step 1:Because this is a square pyramid, what you see above essentially becomes what you see below.</em>

<em />s_l = 2(3.5√(3.5/2)² + 6²)

<em>Step 2: Divide 3.5 by 2 to get 1.75.</em>

<em />s_l<em> </em>= 2(3.5√1.75² + 6²)

<em>Step 3: Square both 1.75 and 6 to get 3.0625 and 36 respectively.</em>

s_l = 2(3.5√3.0625 + 36)

<em>Step 4: Add 3.0625 and 36 to get 39.0625.</em>

<em />s_l = 2(3.5√39.0625)

<em>Step 5: The square root of 39.0625 is 6.25.</em>

<em />s_l<em> </em>= 2(3.5 * 6.25)

<em>Step 6: Multiply 3.5 by 6.25 to get 21.875.</em>

<em />s_l = 2(21.875)

<em>Step 7: Multiply 2 by 21.875 to get 43.75.</em>

<em />s_l = 43.75 ft²

The lateral area of this pyramid is 43.75 ft².

<em />

<em />

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By analyzing the graph of the transformed function, we can see that:

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For a general function f(x), a horizontal translation of N units is written as:

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see the attached figure to better understand the problem

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