Eight goes into seventeen two times with one remaining, and since the denominator always stays the same,

would be your mixed fraction.
11 school days are left.
In the attached picture of a calendar, I marked the days the person has left. There are 11.
Since you don't provide the coordinates of the point W, I will help you in a general form anyway. In the Figure below is represented the segment that matches this problem. We have two endpoints U and V. So, by using the midpoint formula we may solve this problem:

Therefore:

So we know
but we also must know 
Finally, knowing the points U and W we can find the endpoint V.
Answer:
(-10,8)
Step-by-step explanation:
So our original point is (-6,9).
A translation of 4 units to the left means that the x-value would go left by 4. In other words, we subtract 4 to -6. We subtract because going to the left means that it's going to the negative direction.
A translation of down 1 unit means that the y-value would go down by 1. In other words, we subtract 1. Again, we subtract because going downwards means that it's going to the negative direction.
Therefore, the new point would be:

Answer:
the answer is 18 feet because that line in the middle of the triangle is half the size of AC