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3 years ago

Find a normal subgroup of v which is not normal in a4.

1 answer:

6 0

he elements of the Klein 44-group sitting inside A4A4 are precisely the identity, and all elements of A4A4of the form (ij)(kℓ)(ij)(kℓ) (the product of two disjoint transpositions).

Since conjugation in SnSn (and therefore in AnAn) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.

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After reading ¾ of a magazine on Sunday, 0.2 of the remainder on Monday, and 10 pages on Tuesday, Michael still had to read 42 p

icang [17]

Answer:

3 /4 of 2 is the answer to the question

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2 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 419 gram setting. It is

Dahasolnce [82]

Answer:

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

Step(i):-

Given the mean of the Population(μ) = 419 grams

The sample size 'n' =19

Given mean of the sample x⁻ = 412

Given variance of the sample S² = 784

S = √784 = 28

Step(ii):-

Null hypothesis: H₀: There is no sufficient evidence to support the claim that the bags are underfilled.

Alternative hypothesis: H₁:

There is sufficient evidence to support the claim that the bags are underfilled.

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{412 -419}{\frac{28}{\sqrt{19} } }$

t = -1.09

|t| = |-1.09|

Degrees of freedom ν = n-1 = 19-1 =18

t₀.₀₂₅ = 3.19

Final answer:-

The calculated t- value = 1.09 > 3.19 at 0.025 level of significance

Null hypothesis is rejected

There is sufficient evidence to support the claim that the bags are underfilled

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3 years ago

In the diagram m angle ACB = 61 Find m angle BCD

Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer

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