I personally think it is <span>f(t) = 17.5 sin (π/4)(-t+6) + 17.5 </span>
2 and 2/4 = 10/4
10/4 ÷ 1/4 = 10/4 × 4/1 = 10 cups
To solve this we are going to use a conversion factor. We know that 1 BTU per hour is approximately 778 foot-pounds of energy per hour, so our conversion factor will be:

.
Now we just need to multiply <span>4000 BTU by our conversion factor:
</span>

<span>
We can conclude that the furnace released </span><span>
3,112,000 foot pounds of energy in one hour.</span>
Answer:
Step-by-step explanation: