Multiplying polynomials
(3x-8) (2x-2)
2 answers:
When multiplying polynomials, use a process called FOIL
First
Outer
Inner
Last
(3x-8)(2x-2)
Multiply the two first numbers:
3x*2x=6x^2
Multiply the two outer numbers:
3x*-2=-6x
Multiply the two inner numbers:
-8*2x=-16x
Multiply the two last numbers:
-8*-2=16
Now add all your answers together:
6x^2-6x-16x+16
Simplify:
6x^2-22x+16
And there's your answer.
(3x - 8)(2x - 2)
(6x² - 6x - 16x + 16)
6x² - 22x + 16
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