Question

Multiplying polynomials (3x-8) (2x-2)

Answer 1

When multiplying polynomials, use a process called FOIL

First

Outer

Inner

Last

(3x-8)(2x-2)

Multiply the two first numbers:

3x*2x=6x^2

Multiply the two outer numbers:

3x*-2=-6x

Multiply the two inner numbers:

-8*2x=-16x

Multiply the two last numbers:

-8*-2=16

Now add all your answers together:

6x^2-6x-16x+16

Simplify:

6x^2-22x+16

And there's your answer.

Answer 2

(3x - 8)(2x - 2)
(6x² - 6x - 16x + 16)
6x² - 22x + 16