Answer: A reflection across the x-axis keeps the x-coordinates the same but flips the signs of the y-coordinates. So, it should be the opposite for a reflection across the y-axis. The y-coordinates remain the same, but the signs of the x-coordinates change.
Step-by-step explanation
I copy and pasted the answer
Answer:
(3x-1)(2x+1)
Step-by-step explanation:
1-6x^2-x=0
-6x^2-x+1=0
6x^2+x-1=0
6x^2+(3-2)x-1=0
6x^2+3x-2x-1=0
3x(2x+1)-1(2x+1)=0
(3x-1)(2x+1)=0
So the factor is (3x-1)(2x+1)
First, find out x
x+15+2x+15=180
3x+30=180
3x=150
x=50
so the two angels are x+15=65(let's name is ∠5 for convenience), and ∠6= 2x+15=115
notice the two inner lines are marked as congruent, so
∠4=∠5=65
∠1=180-∠4-∠5=180-65-65=50
Name the right bottom angle ∠7, ∠3=∠7 and ∠3+∠7=the exterior angle 100 degree, therefore, ∠3=50
∠2+∠3=∠4, therefore, ∠2=∠4-∠3=65-50=15
∠1=50, ∠2=15, ∠3=50, ∠4=65
The answer to the question is
