Answer:
-6
Step-by-step explanation:
It is given in the question that,
![a_{1} = 2, r = \sqrt 3](https://tex.z-dn.net/?f=a_%7B1%7D%20%3D%202%2C%20r%20%3D%20%5Csqrt%203)
Since we have the value of r given, so we have to use the formula to find the nth term of the geometric progression, which is
![a_{n} = a(r)^{n-1}](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%20a%28r%29%5E%7Bn-1%7D)
Substituting the values of a and r, we will get
![a_{n} = 2( \sqrt 3)^{n-1}](https://tex.z-dn.net/?f=a_%7Bn%7D%20%3D%202%28%20%5Csqrt%203%29%5E%7Bn-1%7D)
So the correct option is the third option .
Answer:
I think it is in order
Step-by-step explanation:
not to sure though sorry
Answer:
The rearrangement can be 45, 987 , 310
Step-by-step explanation:
Here, we want to rearrange the number such that 9 is worth 10 times as what it is worth presently
The value of 9 presently is 90,000
So 10 times as worth will be 10 * 90,000 = 900,000
So we can have the new arrangement as;
45, 987, 310
The correct answer to this problem is
C=3
Y=3