Answer:
Bounce 1 , pass 3, emb2
Explanation:
(By the way I am also doing that question on College board physics page) For the Bounce arrow, since it bumps into the object and goes back, it means now it has a negative momentum, which means a larger momentum is given to the object. P=mv, so the velocity is larger for the object, and larger velocity means a larger kinetic energy which would result in a larger change in the potential energy. Since K=0.5mv^2=U=mgh, a larger potential energy would have a larger change in height which means it has a larger angle θ with the vertical line. Comparing with the "pass arrow" and the "Embedded arrow", the embedded arrow gives the object a larger momentum, Pi=Pf (mv=(M+m)V), it gives all its original momentum to the two objects right now. (Arrow and the pumpkin), it would have a larger velocity. However for the pass arrow, it only gives partial of its original momentum and keeps some of them for the arrow to move, which means the pumpkin has less momentum, means less velocity, and less kinetic energy transferred into the potential energy, and means less change in height, less θangle. So it is Bounce1, pass3, emb2.
No. The DEPENDENT variable is the only one that DEPENDS on
the other one.
The INdependent variable doesn't depend on anything; it doesn't
change until YOU change it.
Answer:
Because here is a number of electrons more applied to the balloon
False. It does repeat itself
Answer:
Explanation:
given,
diameter of inlet = 11.2 cm
r₁ = 5.6 cm
r₁ = 0.056 m ∵ 1 cm = 0.01 m
speed of inlet = 5 m/s
diameter of outlet = 17.5 cm
r₂ = 8.75 cm
r₂ = 0.0875 m ∵ 1 cm = 0.01 m
speed of outlet = ?
using continuity equation
A₁ v₁ = A₂ v₂
π r₁² v₁ = π r₂² v₂
Velocity of liquid at the outlet of the tube is equal to 3.2 m/s
