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AysviL [449]
2 years ago
9

A car traveled at an average velocity of 97 km/hr. If it traveled for 4 hrs, how far did the driver get?

Physics
2 answers:
-BARSIC- [3]2 years ago
5 0

The car's average <em>speed</em> is 97 km/hr.

Then for calculation purposes, we can assume that it covers 97 km in the
first hour, 97 km in the second hour, 97 km in the third hour, and 97 km in
the fourth hour.

All together, the car covers (97 x 4) = <em>388 km</em> of distance.

We don't know the car's velocity, because we have no information about the
<em>direction</em> it moved at any time during the four hours.  So we have no way to
calculate how far it was from the starting point at the end of the fourth hour.
For all we can tell, if the direction (and therefore the velocity) varied just right,
the car could have ended up exactly where it started.


Nimfa-mama [501]2 years ago
5 0
I think the answer is 388 because i multiplyed 97 by 4
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g A motorist traveling at 30.0 m/s passes a stationary police car. The police car gives chase 2.0 s later, accelerating at 5.0 m
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The time for the police car to catch up with the speeding motorist is 7.6 seconds.

<h3>What time will the police car catch up with the speeding motorist?</h3>

The police car and the motorist will cover equal distances.

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Distance covered by the motorist  = speed * time

time = t, speed = 30 m/s

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Distance covered by the police car = acceleration * (time)

time = t - 2, acceleration = 5.0 m/s²

d = 5(t-2)²

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