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AysviL [449]
3 years ago
9

A car traveled at an average velocity of 97 km/hr. If it traveled for 4 hrs, how far did the driver get?

Physics
2 answers:
-BARSIC- [3]3 years ago
5 0

The car's average <em>speed</em> is 97 km/hr.

Then for calculation purposes, we can assume that it covers 97 km in the
first hour, 97 km in the second hour, 97 km in the third hour, and 97 km in
the fourth hour.

All together, the car covers (97 x 4) = <em>388 km</em> of distance.

We don't know the car's velocity, because we have no information about the
<em>direction</em> it moved at any time during the four hours.  So we have no way to
calculate how far it was from the starting point at the end of the fourth hour.
For all we can tell, if the direction (and therefore the velocity) varied just right,
the car could have ended up exactly where it started.


Nimfa-mama [501]3 years ago
5 0
I think the answer is 388 because i multiplyed 97 by 4
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An 18.5-cm-diameter loop of wire is initially oriented perpendicular to a 1.5-T magnetic field. The loop is rotated so that its
nikdorinn [45]

Answer:

The average induced emf in the loop is 0.20 V

Explanation:

Given:

Radius of loop r = \frac{d}{2} = 9.25 \times 10^{-2} m

Magnetic field B = 1.5 T

Change in time \Delta t = 0.20 sec

According to the faraday's law,

Induced emf is given by

    \epsilon = -\frac{\Delta \phi}{\Delta t}

Where \phi = magnetic flux

  \phi = BA\cos0                                ( here \theta = 0 )      

Where A = \pi r^{2}

We neglect minus sign because it's shows lenz law

   \epsilon  = \frac{B \pi r^{2}  }{\Delta t}

   \epsilon = \frac{1.5 \times 3.14 \times (9.25 \times 10^{-2} )^{2} }{0.20}

   \epsilon = 0.20 V

Therefore, the average induced emf in the loop is 0.20 V

4 0
3 years ago
What effect does increasing mass have on the amount of friction generated
LekaFEV [45]
The greater the mass, the greater the fiction generated
4 0
3 years ago
Which is a diatomic molecule? <br> A. Ar <br> B. CO <br> C. CO2 <br> D. NaCl
snow_tiger [21]

Answer: B. CO

Explanation:

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In this sense, oxygen is a homonuclear diatomic molecule because it is formed by two atoms of the same element (O_{2}) and Carbon monoxide (CO) is heteronuclear diatomic molecule.

Sodium Chloride NaCl is not a diatomic molecule because is a product of ionization, but it can be diatomic in its gas phase with a polar covalent bond.

3 0
3 years ago
A physics student throws a softball straight up into the air. The ball was in the air for a total of 3.56 s before it was caught
meriva

Answer:

The initial velocity of the softball is 14.711 meters per second.

Explanation:

This is a case of an object which experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from air friction and Earth's rotation can be neglected.

From statement we must understand that the student threw the softball upwards and it is caught at original position 3.56 seconds later. Initial and final heights, time and gravitational acceleration are known and initial speed is unknown. The following equation of motion is used:

y = y_{o} + v_{o}\cdot t + \frac{1}{2}\cdot g \cdot t^{2} (Eq. 1)

Where:

y_{o} - Initial height of the softball, measured in meters.

y - Final height of the softball, measured in meters.

v_{o} - Initial velocity of the softball, measured in meters per second.

t - Time, measured in seconds.

g - Gravitational acceleration, measured in meters per square second.

If we know that y = y_{o}, t = 3.56\,s and g = -9.807\,\frac{m}{s^{2}}, the initial velocity of the softball is:

v_{o}\cdot (3\,s)+\frac{1}{2}\cdot (-9.807\,\frac{m}{s^{2}} )\cdot (3\,s)^{2} = 0

3\cdot v_{o} -44.132\,m= 0

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The initial velocity of the softball is 14.711 meters per second.

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Dafna1 [17]

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7 0
3 years ago
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