To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation.
Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds
Horizontal distance
=0.335s*1.2m/s
=0.402 meters
1. Resonance. Mechanical waves act on or through a medium, these waves can often have frequencies that are synchronized in a way that makes them act on the matter in the medium more "aggressively."
Answer:
The tension in the string is equal to Ct
And the time t0 when the rension in the string is 27N is 3.6s.
Explanation:
An approach to solving this problem jnvolves looking at the whole system as one body by drawing an imaginary box around both bodies and taking summation of the forces. This gives F2 - F1 = Ct. This is only possible assuming the string is massless and does not stretch, that way transmitting the force applied across it undiminished.
So T = Ct
When T = 27N then t = T/C = 27/7.5 = 3.6s
Answer:
2.1 × 10⁻⁵ T
Explanation:
Given:
Inner radius, r = 4 mm = 0.004 m
Outer radius, R = 25 mm = 0.025 m
Current, I = 4 A
Distance of the point from the center, a = 17 mm = 0.017 m
μ₀ = 4π × 10⁻⁷ T·m/A
Now,
For the hollow cylinder magnetic field (B) is given as:
on substituting the respective values, we get
or
B = 2.1 × 10⁻⁵ T
Answer:
Option D.) 5.0 x 10^-4m
Explanation:
Data obtained from the question include:
f (frequency) = 6 x 10^11 Hz
v (velocity) = 3.00 x 10^8 m/s
λ (wavelength) =?
Using the equation v = λf, the wavelength can be obtained as illustrated below:
v = λf
λ = v/f
λ = 3.00 x 10^8/6 x 10^11
λ = 5 x 10^-4m
Therefore, the wavelength of the beam of the electromagnetic radiation is 5 x 10^-4m
