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frozen [14]
2 years ago
15

Help me with this question please

Physics
1 answer:
erma4kov [3.2K]2 years ago
4 0

Answer:

flrrflkmfcolmuunoijhijbihbihbihbhibihbijbiubiubih igbo no publicó uib

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Colonist who belived in complete​
velikii [3]

Answer:

Natural right

Explanation:

That  is all what i know

5 0
3 years ago
How does the balanced chemical equation show the conservation of matter in the chemical reaction?
Dmitry [639]

C. The number of F atoms in the reactants equals the number of F atoms in the products.

4 0
2 years ago
1) Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way ba
timurjin [86]

Answer:

<h3>B. 19miles</h3>

Explanation:

If Freddy drives 4 miles east to his friend's house. He then travels 9 more miles east to the supermarket. Finally on his way back home he out  of gas 6 miles after leaving the supermarket, the distance travel by fred will be the sup of all the distances he covered throughout the journey.

Distance covered by fred = 4miles + 9miles + 6miles

Distance covered by fred = 13miles + 6miles

Distance covered by fred  = 19miles

8 0
3 years ago
Which nucleus completes the following equation?
natka813 [3]
the answer is C




IGNORW irritating but not even on the golden bath bath and
3 0
3 years ago
You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp
GenaCL600 [577]

Answer:

(a)11.24 m/s

(b)7.44 m/s

(c)409 N

(d)539.55\mu

(e) 0

Explanation:

The period for 1 circle 2\pi of the merry go around is 9.5s. It means the angular speed is:

\omega = \theta / t = 2\pi / 9.5 \approx 0.661 rad/s

(a)The speed is

v = \omega * R = 0.661 * 17 = 11.24 m/s

(b) Centripetal acceleration:

a = \frac{v^2}{R} = \frac{11.24^2}{17} = 7.44 m/s^2

(c) Magnitude of the force that keeps you go around at this acceleration

F = ma = 55 * 7.44 = 409 N

(d) let the coefficient of friction by \mu. The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

F_f = mg\mu = 55*9.81\mu = 539.55\mu

3 0
2 years ago
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