Question

A liquid enters one end of a tube, where the diameter is

Answer 1

Answer:

 $v_2=3.2\ m/s$

Explanation:

given,

diameter of inlet = 11.2 cm

                     r₁ = 5.6 cm

                     r₁ = 0.056 m       ∵ 1 cm = 0.01 m  

speed of inlet = 5 m/s

diameter of outlet = 17.5 cm

                    r₂ = 8.75 cm

                    r₂ = 0.0875 m       ∵ 1 cm = 0.01 m  

speed of outlet = ?

using continuity equation

 A₁ v₁ = A₂ v₂

 π r₁² v₁ = π r₂² v₂

 $v_2= \dfrac{r_1^2}{r_2^2} v_1$

 $v_2= \dfrac{0.056^2}{0.0875^2} v_1$

 $v_2= 0.64 v_1$

 $v_2= 0.64\times 5$

 $v_2=3.2\ m/s$

Velocity of liquid at the outlet of the tube is equal to 3.2 m/s