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gtnhenbr [62]
2 years ago
7

, 80 POINTS Find k so that P(k,0) is equidistant from points A(1,2) and B(2,5).

Mathematics
1 answer:
blagie [28]2 years ago
8 0

Answer:

P(1.5, 3.5)

Step-by-step explanation:

We need to find the average of the x and y coordinates. We do this by adding the two values, then dividing by two:

P(x1 + x2/ 2, y1 + y2/2) = P(1 + 2/ 2, 2 + 5/ 2) = P(3/2, 7/2) = P(1.5, 3.5)

These are our coordinates!

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Answer:

The correct option is B.

Step-by-step explanation:

From the given figure it is nices that the length of sides AB, BC and AC are 20, 22 and 35. The line AD is angle bisector.

Let the missing value be x.

The Triangle Angle Bisector Theorem states that the angle bisector of an angle of a triangle divides the opposite side in two segments that are proportional to the other two sides of the triangle.

Since AD is angle bisector, therefore

\frac{AB}{AC}=\frac{BD}{CD}

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20x=35(22-x)

20x=770-35x

Add 35x both sides.

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Divide both sides by 55.

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Therefore, second option is correct.

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3 years ago
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Answer:

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Step-by-step explanation:

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2 years ago
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Answer:

Step-by-step explanation:

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