, 80 POINTS Find k so that P(k,0) is equidistant from points A(1,2) and B(2,5).
1 answer:
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Answer:
The remainder would be 1 or 3
Step-by-step explanation:
Consider the 5 consecutive positive integers are,
x, x + 1, x + 2, x + 3, x + 4,
Since, the average of these 5 numbers =
= x + 2
If x + 2 = odd,
⇒ x = odd - 2 = odd - even = odd
⇒ x + 4 = odd + even = odd
∵ an odd number is represented by '2n + 1'
Where, n = 0, 1, 2, 3, ........
Now, 2n + 1 = 1( mod 4) if n = even
While, 2n + 1 = 3( mod 4) if n = odd,
Hence, when the largest of the five integers is divided by 4 remainder would be 1 or 3.