x adds 1 and y subtracts by 6
The area of an equilateral triangle of side "s" is s^2*sqrt(3)/4. So the volume of the slices in your problem is
(x - x^2)^2 * sqrt(3)/4.
Integrating from x = 0 to x = 1, we have
[(1/3)x^3 - (1/2)x^4 + (1/5)x^5]*sqrt(3)/4
= (1/30)*sqrt(3)/4 = sqrt(3)/120 = about 0.0144.
Since this seems quite small, it makes sense to ask what the base area might be...integral from 0 to 1 of (x - x^2) dx = (1/2) - (1/3) = 1/6. Yes, OK, the max height of the triangles occurs where x - x^2 = 1/4, and most of the triangles are quite a bit shorter...
Find the mean, median, and mode of the data set. Round to the nearest tenth. 15, 13, 9, 9, 7, 1, 11, 10, 13, 1, 13 mean = 8.5, m
jasenka [17]
Answer:
Mean = 9.3
Median = 10
Mode = 13
Step-by-step explanation:
To get the mean, you would have to add up all of the numbers (102), then divide how many numbers you have with the numbers added up (9.3). To get the median, you would have to put all of the numbers that you have, in order, from least to greatest and cross off each number, one from each side before getting to the number in the middle (unless if you have an even number; works better with odd numbers, which is easier). To get the mode, you would need to find out which number appears the most, and, if there is more than one, you can put the numbers down. Hope this helps.
79 is 4 below 83 so her next grade needs to be 4 above in order to get an average of 83. The answer is 87.
