The value of 2 is two thousand
Answer:
Step-by-step explanation:
To solve this correctly, you need to make sure to distribute the negative onto both terms in the second parentheses.
So fully expanded, the problem would be:
2y² + 8y -7 + 3y - 3 = ?
You can easily rearrange the terms, or just do it in your head!
It would become:
2y² + 8y +3y -7 -3
= 2y² + 11y -10
Make sure you keep the terms with different variables separate! I hope this is helpful!
Answer:
D. ax-b<-c or ax-b>c is the correct answer.
Step-by-step explanation:
<h3>
Answer: Choice B</h3>
The set notation includes all values from -5 to 0, but the domain only includes the integer values
eg: something like -1.2 is in the second set, but it is not in the set {-5,-4,-3,-2,-1}
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Further explanation:
Let's go through the answer choices one by one
- A. This is false because 0 does not come before -5, but instead -5 is listed first. The order -5,-4,-3,-2,-1,0 is correct meaning that
is the correct order as well. - B. This is true. A value like x = -1.2 is in the set
since -1.2 is between -5 and 0; but -1.2 is not in the set {-5, -4, -3, -2, -1, 0}. So the distinction is that we're either considering integers only or all real numbers in this interval. To ensure that we only look at integers, the student would have to write 
. The portion 
means "x is in the set of integers". The Z refers to the German word Zahlen, which translates to "numbers". - C. This is false. The student used the correct inequality signs to indicate x is -5 or larger and also 0 or smaller; basically x is between -5 and 0 inclusive of both endpoints. The "or equal to" portions indicate we are keeping the endpoints and not excluding them.
- D. This is false. Writing
would not make any sense. This is because that compound inequality breaks down into 
. Try to think of a number that is both smaller than -5 AND also larger than 0. It can't be done. No such number exists.
Answer:-9
Step-by-step explanation:
