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zzz [600]
3 years ago
10

Robert is hosting a backyard barbecue. He uses a charcoal fire to grill the chicken. The chicken cooks, but it never touches the

fire directly. What energy transformation occurs as the chicken cooks? A. chemical potential energy → radiant energy → thermal energy B. thermal energy → chemical potential energy → motion energy C. chemical potential energy → electric potential energy D. motion energy → chemical potential energy → motion energy E. radiant energy → electric potential energy → chemical potential energy
Biology
2 answers:
oksian1 [2.3K]3 years ago
7 0

to my understanding the answer is A

Colt1911 [192]3 years ago
5 0

When grilling chicken using charcoal fire, the energy transformation that takes place starts from chemical energy, to radiant energy and then thermal energy. The combustion reaction of the charcoal fire converts the chemical energy into heat. The charcoal fire is considered as radiant energy. Lastly, burning fuels like coal or wood produces thermal energy, and that thermal energy is basically the reason why the chicken was cooked even without directly touching the fire.

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At the end of cytokinesis, how many daughter chromosomes will be found in each cell
trapecia [35]
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Whereas at the end of Mitosis there are 2 identical DIPLOID sister cells.

Sources~ yahoo answers
And just now learned it last week

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4 0
3 years ago
In a population of plants, the allele for long stems is completely dominant over the allele for short stems. If 35% of the popul
KatRina [158]
Assumptions:
1. Equilibrium has been reached for the allele proportions
2. Absence of <span>evolutionary influences such as </span>mate choice<span>, </span>mutation<span>, </span>selection<span>, </span>genetic drift<span>, </span>gene flow<span> and </span>meiotic drive<span>.
</span>
Defining L=long stem, l=short stem, and L is dominant over l.
f(x) = frequency of allele x  (expressed as a fraction of population)
Then the Hardy-Weinberg equilibrium law applies:
p^2+2pq+q^2=1
where 
f(LL)=p^2
f(Ll)=2pq
f(ll)=q^2

Given f(ll)=0.35=q^2, we have
q=sqrt(0.35)=0.591608
p=1-q=0.408392
=>
f(Ll)
=2pq
=2*0.408392*0.591608=0.483216
= proportion of heterozygous population

Answer: percentage of heterozygous population is 48.32%
7 0
3 years ago
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Bas_tet [7]
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Cloud [144]

Answer:

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Solnce55 [7]

Answer:

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