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Elan Coil [88]
4 years ago
10

Divide 4/5÷6/7 to the simplest firm

Mathematics
2 answers:
Sati [7]4 years ago
5 0

4/5÷6/7

= 4/5 x 7/6

= 28/30

= 14/15


Hope it helps.

marta [7]4 years ago
3 0

The simplest form is 14/15



4/5÷6/7 Switch the numerator and denominator on ONE fraction.


4/5*7/6 Multiply.


28/30 Simplify.


14/15 Done.

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The graph depicts the growth and costs using of line segment use the midpoint formula to approximate the cost during the year 19
marysya [2.9K]

Answer:

The approximate cost during the year 1987 was $7,533

Step-by-step explanation:

The complete question in the attached figure

we have

y -----> is the cost in dollars

x -----> is the year

Looking at the graph we have the points

(1983,5,047) and (1991, 10,019)

To determine the cost in the year 1987, find out the midpoint between the two given points

The formula to calculate the midpoint between two points is equal to

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

substitute the values

M=(\frac{1983+1991}{2},\frac{5,047+10,019}{2})

M=(1987,7,533)

therefore

The approximate cost during the year 1987 was $7,533

7 0
3 years ago
A 2 digit number is one more than 6 times the sum of its digits. If the digits are reversed, the new number is 9 less than the o
atroni [7]

10a+b=c,

c=6*(a+b)+1,

10b+a=c-9

a = 4, b = 3, c = 43

8 0
3 years ago
What is the solution to this equation 8x^2 - 3 = √16x+9
rusak2 [61]

Answer:x=3/2 or -1

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
A certain radioactive isotope has a half-life of 15 days. If one is to make a table showing the half-life decay of a sample of t
Verdich [7]
A half-life of the isotope is 15 days and at start its mass is 32 g.
A table:
              t:                 m:
              0                32 g
             15               16 g
             30                 8 g
             45                 4 g
             60                 2 g
             75                 1 g
In the first column is used an arithmetic sequence ( a 1 = 0, d = 15 ).
In the second column is used a geometric sequence ( a 1 = 32, r = 1/2 )                       
7 0
3 years ago
Determine the currents in the picture
Elenna [48]

Answer:

The value of currents are I_1=0A, I_2=1A and I_3=1A.

Step-by-step explanation:


The Ohm's law states that

V=IR

it is given that the V₁=3V and V₂=4V.

In a parallel circuit:

  • Voltage is same in each component
  • Sum of the currents equals to the total current that flows.

I_2=I_1+I_3                   .... (1)

Equation for first loop is,

V_1=4I_1+3I_2

3=4I_1+3I_2              ..... (2)

Equation for second loop is,

V_2=1I_3+3I_2

4=1I_3+3I_2             ..... (3)

On solving (1), (2) and (3) we get

I_1=0


I_2=1

I_3=1

Therefore the value of currents are I_1=0A, I_2=1A and I_3=1A.

6 0
3 years ago
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