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mariarad [96]
4 years ago
13

Which of the following is the coefficient in the algebraic expression 2x+y4 A.4 B.x C.2 D.y?

Mathematics
1 answer:
Firlakuza [10]4 years ago
5 0
Is the last part y to the 4th power? If it is I like to write it y^4 to avoid confusion.
So anyway the coefficient is the number accompanying the variable so the answer is C. 2  

Hope this helps.
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Sofia wrote three numbers between 0.77 and 0.78 what numbers Sofia
Ostrovityanka [42]

Answer:

0.771, 0.772, 0.773

Step-by-step explanation:

three numbers between 0.77 and 0.78

0.77 = 0.770

and

0.78 = 0.780

So,

0.770, 0.771, 0.772, 0.773, 0.780

= 0.77, 0.771, 0.772, 0.773, 0.78

5 0
3 years ago
Find the slope of the line that contains the points (6, -2) and (-3, 7).
Ira Lisetskai [31]
Slope = (y2 - y1)/(x2 - x1)
slope = (7 - -2)/(-3 - 6)
slope = 9/-9
slope = -1
4 0
4 years ago
What is the mean for the data shown in the dot plot? 4 5 6 10
RSB [31]

Answer:

Mean = 6.25

Step-by-step explanation:

Data values: 4, 5, 6, 10

Mean = (Sum of all values)/(Number of values)

Mean = (4 + 5 + 6 + 10)/4

Mean = 25/4

Mean = 6.25

3 0
3 years ago
Read 2 more answers
If x Is a real number such that x3 = 64, the x2 + x equals what?
Annette [7]

Answer:

20

Step-by-step explanation:

Assuming that the equation is x³ = 64, that can be solved by putting cube root on both sides like so: ∛(x³) = ∛64, which simplifies to <em>x = 4</em>.

Plugging that into our expression gives us <em>4² + 4</em>, which is 20.

7 0
3 years ago
The mean preparation fee H&amp;R Block charged retail customers in 2012 was $183 (The Wall Street Journal, March 7, 2012). Use t
astraxan [27]

Answer:

a)0.6192

b)0.7422

c)0.8904

d)at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

Step-by-step explanation:

Let z(p) be the z-statistic of the probability that the mean price for a sample is within the margin of error. Then

z(p)=\frac{ME*\sqrt{N}}{s } where

  • Me is the margin of error from the mean
  • s is the standard deviation of the population
  • N is the sample size

a.

z(p)=\frac{8*\sqrt{30}}{50 } ≈ 0.8764

by looking z-table corresponding p value is 1-0.3808=0.6192

b.

z(p)=\frac{8*\sqrt{50}}{50 } ≈ 1.1314

by looking z-table corresponding p value is 1-0.2578=0.7422

c.

z(p)=\frac{8*\sqrt{100}}{50 } ≈ 1.6

by looking z-table corresponding p value is 1-0.1096=0.8904

d.

Minimum required sample size for 0.95 probability is

N≥(\frac{z*s}{ME} )^2 where

  • N is the sample size
  • z is the corresponding z-score in 95% probability (1.96)
  • s is the standard deviation (50)
  • ME is the margin of error (8)

then N≥(\frac{1.96*50}{8} )^2 ≈150.6

Thus at least 151 sample is needed for 95% probability that sample mean falls within 8$ of the population mean.

7 0
3 years ago
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