<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Circle = (x-h)^2 + (y-k)^2 = r^2
Center is (h,k) h = -5, k = 2
Radius is 4, r = 4
(x - -5)^2 + (y - 2)^2 = 4^2
(x + 5)^2 + (y - 2)^2 = 16
Answer:
gotta be answer A
Step-by-step explanation:
you can search up f(x) = square root of x
The answer is: cosV=39/89=0,43
Answer:
2x
Step-by-step explanation:
