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katovenus [111]
2 years ago
10

Fourteen school festival tickets were sold to adults and children. A total of $38 was collected from these ticket sales. Adult t

ickets cost $4 each, and child tickets cost $1 each. If x represents the number of adult tickets sold and y represents the number of child tickets sold, which of the following systems of equations represents this situation?
A. x + y = 38
4x + y = 14

B. 4x + y = 38
x + y =14

C. 2x + y = 14
y - x = 38

D. x + 2y = 14
y - 2x = 38​
Mathematics
1 answer:
spayn [35]2 years ago
8 0

Answer:

A

Step-by-step explanation:

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How much simple interest would 1000 earn in 275 days at an interest rate of 4.21%
nikitadnepr [17]
Now, there are 365 (excluding leap years) in a year, so, 275 days is not even a year, but is  275/365 of a year, or 55/73 of a year.

\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\\
P=\textit{original amount deposited}\to& \$1000\\
r=rate\to 4.21\%\to \frac{4.21}{100}\to &0.0421\\
t=years\to \frac{275}{365}\to &\frac{55}{73}
\end{cases}
\\\\\\
I=1000\cdot 0.0421\cdot \cfrac{55}{73}
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3 years ago
A truck traveled 232 miles in 4 hours. The truck continued traveling at the same average speed. How many miles,
vlada-n [284]

Answer:

319 miles.

Step-by-step explanation:

4 0
3 years ago
Me podrían ayudar y explicarme el proceso please
kakasveta [241]

Answer: Encontrarás las respuestas debajo de cada explicación. Espero que consideres darme brainliest y 5 estrellas, y más importante, que hayas entendido.

Step-by-step explanation:

Esto es la regla de 3. Conoces 3 valores y necesitas encontrar un 4to valor.

Ya sabemos que 1 caja pesa 20kg,

1 - 20kg

ahora queremos saber cuantas cajas (x) equivalen a 7653kg

x - 7653kg

Hacemos un pequeño cuadro poniendo en un lado los numeros de cajas y del otro el peso.

Pongamos la cantidad de cajas en la izquierda y el peso en la derecha

\frac{1}{x} =\frac{20kg}{7653kg}

Procedemos a multiplicar en cruz. Solo podemos multiplicar si tenemos ambos valores. En este caso, los valores en cruz que tenemos son 1 y 7653kg porque en la otra cruz (20 y x) tenemos nuestra incognita. Y, por ultimo, dividimos entre el numero cuya cruz es con la incognita (20kg)

Esto nos deja la expresión así;

x=\frac{1*7653kg}{20kg}

x=382.65

Como una caja no puede ser un numero decimal, redondeamos.

x=383

Por lo tanto, se necesitan aproximadamente 383 cajas para que su peso equivalga a 7653 kg.

-------------------------------------------------------------------------------------------------------

La otra pregunta dice: Si una caja pesa 20kg, (1 - 20kg), ¿Cuántas cajas se necesitan para equivaler 9500kg? (x - 9500kg)

Hacemos lo mismo que arriba, ponemos la cantidad de cajas de un lado, y el peso de otro lado.

\frac{1}{x}=\frac{20kg}{9500kg}

Multiplicamos aquellos valores en cruz que conozcamos y dividimos por el valor cuya cruz sea con x.

x=\frac{1*9500kg}{20kg}

x=475

Esta es la cantidad de cajas que se necesitan para que su pesa equivalga a 9500kg.

--------------------------------------------------------------------------------------------------------

Por último, la pregunta dice, ¿Cuántos kilogramos hay en 873 cajas?

Ya sabemos que una caja pesa 20kg ( 1 - 20kg ) y ahora buscamos cuantos kg hay en 873 cajas; es decir, (873 - x)

Nos quedaría así;

\frac{1}{873}=\frac{20kg}{x}

Ahora, nuestra cruz es 873 y 20kg, y el divisor es 1.

x=\frac{873*20kg}{1}

x=17460kg

Este sería el peso de 873 cajas.

5 0
3 years ago
A stage in the shape of a semi circle had a diameter of 42 ft. What is area of the stage? Use 22/7 for π. PLZ I NEED FAST TEST
zavuch27 [327]

A semi circle is half a full circle. Find the area of the full circle and divide it by 2.

Area of a circle = pi x r ^2

R is half the diameter

Area of full circle:

Area = 22/7 x 21^2

Area = 1386 sq. Ft

Area of stage = 1386/2 = 693 square feet

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3 years ago
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100 points!!! Show your work on paper
lyudmila [28]

Answer:

  • 10 cm, 15 cm

Step-by-step explanation:

Set ratios and solve for x

<u>Corresponding sides are AC with A'C' and CB with C'B'</u>

  • AC/A'C' = CB/C'B'
  • (x - 1)/2 = (x + 4)/3
  • 3(x - 1) = 2(x + 4)
  • 3x - 3 = 2x + 8
  • 3x - 2x = 8 + 3
  • x = 11

<u>Find the values of AC and CB:</u>

  • AC = x - 1 = 11 - 1 = 10 cm
  • CB = x + 4 = 11 + 4 = 15 cm
5 0
3 years ago
Read 2 more answers
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