For the reaction 2 HCl + Na2CO3 → 2 NaCl + H2O + CO2 8.0 moles of CO2 is collected at STP. What is the volume of CO2? 1. 57.6 L 2. 22.4 L 3. 0.0250 L 4. 2.80 L 5. 179 L 6. 0.357 L
1 answer:
Answer:
Option 5. 179L
Explanation:
The reaction is:
2 HCl + Na₂CO₃ → 2NaCl + H₂O + CO₂
The amount of collected CO₂ is 8 moles.
We apply the Ideal Gases Law at STP
STP are 1 atm of pressure and 273K of T°
P . V = n . R . T
1atm . V = 8 mol .0.082L.atm/mol.K . 273K
V = (8 mol .0.082L.atm/mol.K . 273K) / 1 atm = 179 L
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As we know that <span>V1/T1 = V2/T2 V1 = 9.10 L T1 = 471 K V2 = 2.50 L T2 = 2.5 x 471 / 9.10 = 129.3 K T2 = 129.3 - 273 = -143.6 deg Celsiu hope it helps</span>