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Sedbober [7]
3 years ago
8

Both hydrogen sulfide (H2S) and ammonia (NH3) have strong, unpleasant odors. Which gas has the higher effusion rate? If you open

ed a container of each gas in a corner of a large room, which odor would you detect first on the other side of the room? Assume the temperature is constant. Explain your answer.
Chemistry
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

yooooo D kardi

Explanation:

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Which of the following hypotheses cannot be tested using the scientific method
Arturiano [62]
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
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Alkynes are hydrocarbons with at least one triple covalent bond.
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A gaseous substance turns directly into a solid. Which term describes this change?.
zavuch27 [327]

Answer:

Deposition

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Deposition: The gaseous substance turns directly into a solid without undergoing the liquid phase

3 0
2 years ago
John is outstanding forward on his club select soccer team. He is know for his ball control and speed. After a game he often mak
natima [27]

Answer:

This self evaluation helps them to better his sport.

Explanation:

This is the right way to evaluate the performance of John because this sketch shows him the way he perform in the match. Due to this sketch he can better his performance and remove all the mistakes he had done in the match which results in better performance of John in the next match. This self evaluation helps them to better his sport and got new chances in order to select for a better club or national soccer team.

4 0
3 years ago
What volume of 18.0 m sulfuric acid is required to prepare 16.5 l of 0.126 m h2so4?
Blababa [14]

this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.

the dilution forumla is as follows

c1v1 = c2v2

where c1 is concentration and v1 is volume of the more concetrated solution

c2 is concentration and v2 is volume of the diluted solution

substituting the values in the equation

18.0 M x V = 0.126 M x 16.5 L

V = 0.1155 L

volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.

6 0
3 years ago
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