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3 years ago

Can you guys give some science fair project ideas(8th grade)

1 answer:

5 0

Answer
i’m in 7th grade but for this years science fair i did, “ how does temperature affect the elasticity of rubber bands”

Guide a growing plant through a maze.
8th Grade Science Plant Maze KiwiCo

Prove that plants really do seek out the light by setting up a simple or complex maze. This is a simple 8th grade science project with really cool results.

Blow out a candle with a balloon.

Blowing up a balloon with baking soda and vinegar is the classic acids and bases experiment. Take it a step further by experimenting with the carbon dioxide it produces. (Don’t be afraid of fire in the science

Stand on a pile of paper cups.

Combine physics and engineering and challenge 8th grade science students to create a paper cup structure that can support their weight. This is a cool project for aspiring architects.

hope this helps and have a wonderful day :)

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Li + HNO3 > LiNO3 + H2 how do I balance it? Show work pls

azamat

Answer: The balanced equation is $2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$ .

Explanation:

The given reaction equation is as follows.

$Li + HNO_{3} \rightarrow LiNO_{3} + H_{2}$

Number of atoms present on reactant side are as follows.

Li = 1
H = 1
$NO_{3}$ = 1

Number of atoms present on product side are as follows.

Li = 1
H = 2
$NO_{3}$ = 1

To balance this equation, multiply Li by 2 and $HNO_{3}$ by 2 on reactant side. Also, multiply $LiNO_{3}$ by 2 on product side.

Hence, the equation can be rewritten as follows.

$2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$

Now, number of atoms present on reactant side are as follows.

Li = 2
H = 2
$NO_{3}$ = 2

Number of atoms present on product side are as follows.

Li = 2
H = 2
$NO_{3}$ = 2

As there are same number of atoms on both reactant and product side. Hence, the equation is now balanced.

Thus, we can conclude that the balanced equation is $2Li + 2HNO_{3} \rightarrow 2LiNO_{3} + H_{2}$ .

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3 years ago

Before we can analyze the alum crystal it is

dusya [7]

Answer: TRUE

Explanation:

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3 years ago

A mixture of 2.0 moles of H2, 2.0 moles of NH4, 4.0 moles of CO2, and 5.0 moles of

VARVARA [1.3K]

Answer:

0.01125

Explanation:

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3 years ago

B. How do metals and non-metals differ chemically?<br>1

snow_lady [41]

Non metals can not give electrons to hydrogen in water to be released as H2 gas

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3 years ago

A solution of Cuso, is labelled 1.743 M. How much Cuso, in grams, must be used to make

zepelin [54]

Answer:

Option A. 416.1 g.

Explanation:

Data obtained from the question include the following:

Molarity = 1.743 M

Volume = 1.4957 L

Mass of CuSO4 =..?

Next, we shall determine mole of CuSO4 present in the solution.

This is illustrated below:

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the mole CuSO4 present in the solution as follow:

Molarity = 1.743 M

Volume = 1.4957 L

Mole of CuSO4 =..?

Molarity = mole /Volume

1.743 = mole of CuSO4 /1.4957

Cross multiply

Mole of CuSO4 = 1.743 x 1.4957

Mole of CuSO4 = 2.607 moles

Finally, we shall convert 2.607 moles of CuSO4 to grams.

This can be obtained as follow:

Molar mass of CuSO4 = 63.55 + 32.06 + (16x4) = 159.61 g/m

Mole of CuSO4 = 2.607 moles

Mass of CuSO4 =..?

Mole = mass /molar mass

2.607 = mass of CuSO4 /159.61

Cross multiply

Mass of CuSO4 = 2.607 x 159.61

Mass of CuSO4 = 416.1 g

Therefore, 416.1 g of CuSO4 is needed to prepare the solution.

7 0

3 years ago

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