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2 years ago

9

A campground rents bicycles by the hour. The total cost y to rent a bicycle, including deposit, is presented by the function y=1

/3x+12. Is the function continuous or discrete

1 answer:

Bogdan [553]2 years ago

3 0

The function is discrete, as the fee is charged based on the hours

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Show work please~

love history [14]

For every 1 cup of blue paint, $\frac{10}{4}$ cups of red paint are needed

For every 1 cup of red paint, $\frac{4}{10}$ cup of blue paint is needed

For every 4 cups of red paint, $\frac{16}{10}$ cups of blue paint are needed

<em><u>Solution:</u></em>

Given that, there are 3 1/3 red cups of paint for every 1 1/3 cups of blue paint

Therefore, ratio is

$Red : blue = 3\frac{1}{3} : 1\frac{1}{3}\\\\Red : blue = \frac{10}{3} : \frac{4}{3}$

<h3><u>For every 1 cup of blue paint, ___ cups of red paint are needed</u></h3>

Let "x" be the cups of red paint needed

Then we get,

$\frac{10}{3} : \frac{4}{3}\\\\x : 1$

This forms a proportion

$1 \times \frac{10}{3} = \frac{4}{3} \times x\\\\x = \frac{10}{4}$

Therefore, 10/4 cups of red are needed for 1 cup of blue

<h3><u>For every 1 cup of red paint, ___ cup of blue paint is needed</u></h3>

Let "x" be the cups of blue paint needed

Then, we get

$\frac{10}{3} : \frac{4}{3}\\\\1 : x$

This forms a proportion

$\frac{10}{3} \times x = \frac{4}{3} \times 1\\\\x = \frac{4}{10}$

Thus, 4/10 cups of blue are needed for 1 cup of red paint

<h3><u>For every 4 cups of red paint,___ cups of blue paint are needed</u></h3>

Let "x" be the cups of blue paint needed

Then, we get

$\frac{10}{3} : \frac{4}{3}\\\\4 : x$

This forms a proportion

$\frac{10}{3} \times x = \frac{4}{3} \times 4\\\\x = \frac{16}{10}$

Thus 16/10 cups of blue paint are needed for every 4 cups of red paint

5 0

2 years ago

Turn -1.55 to a mixed number in simplest form

Zanzabum

-1 55/100 then reduce, -1 11/20

5 0

2 years ago

Find the lcm of 9 and 27

ELEN [110]

Answer:

The answer you are looking for is 27.

Step-by-step explanation:

The reason is because 27 is the 3rd multiple of 9.

7 0

2 years ago

Read 2 more answers

Solve the equation for x∈Z <br><br>-x² +8x -14 ≥ 0

kenny6666 [7]

$ax^2+bx+c=0\\\Delta=b^2-4ac\\if\ \Delta < 0\ then\ no\ solutions\\if\ \Delta=0\ then\ one\ solution:x=\frac{-b}{2a}\\if\ \Delta > 0\ then\ two\ solutions:x=\frac{-b\pm\sqrt\Delta}{2a}\\================================\\\\-x^2+8x-14\geq0\ \ \ \ |multiply\ both\ sides\ by\ (-1)\ \{change\ \geq\ on\ \leq\}\\\\x^2-8x+14\leq0\\\\a=1;\ b=-8;\ c=14\\\\\Delta=(-8)^2-4\cdot1\cdot14=64-56=8 > 0\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=\sqrt4\cdot\sqrt2=2\sqrt2$

$x_1=\frac{-(-8)-2\sqrt2}{2\cdot1}=\frac{8-2\sqrt2}{2}=\frac{8}{2}-\frac{2\sqrt2}{2}=\boxed{4-\sqrt2}\\\\x_2=\frac{-(-8)+2\sqrt2}{2\cdot1}=\frac{8+2\sqrt2}{2}=\frac{8}{2}+\frac{2\sqrt2}{2}=\boxed{4+\sqrt2}\\\\============================$

$ax^2+bx+c=0\\\\if\ a > 0\ then\ the\ parabola\ o pen\ up\\if\ a < 0\ then\ the\ parabola\ o pen\ down\\========================\\\\a=1 > 0-therefore\ o pen\ up\ (look\ at\ the\ picture)\\\\===============================\\\\Answer:x\in\left$

$Solutions\ in\ \mathbb{Z}:\\\\\sqrt2\approx1.4\\\\threfore:4-\sqrt2\approx4-1.4=2.6\ and\ 4+\sqrt2\approx4+1.4=5.4\\\\look\ at\ the\ second\ picture:x=3\ or\ x=4\ or\ x=5\ (x\in\{3;\ 4;\ 5\})$

6 0

2 years ago

Read 2 more answers

The local high school is having a talent show. On Monday they sale 5 children tickets and 3 adult tickets for $25 On Tuesday the

Lunna [17]

The adult tickets cost $5 and the child tickets cost $2

Monday
5 x ($2) + 3 x ($5) = $25

Tuesday
4 x ($2) + 4 x ($5) = $28

4 0

2 years ago