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Ilia_Sergeevich [38]
3 years ago
6

Thank you whoever answers! ^ ^​

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:b

Step-by-step explanation:

Isolating means leaving something on one side of the equation. In this situation, one has to subtract the 2t from both sides

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Simplify this problem
ikadub [295]

Answer:

\boxed{  \frac{ \sqrt[3]{ {x}^{11} } }{4} }

Step-by-step explanation:

=  >  \frac{ {x}^{4} }{ \sqrt[3]{64x} }  \\  \\  =  >  \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} }  )\times  ({x}^{ \frac{1}{3} } )}  \\  \\  =  >  \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times(  {x}^{ \frac{1}{3} }  )}  \\  \\  =  >   \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times  \frac{1}{ \cancel{3}} } ) \times(  {x}^{ \frac{1}{3} }  )}   \\  \\  =  >  \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } }  \\  \\  =  >  \frac{ {x}^{4 -  \frac{1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{12 - 1}{3} } }{4}  \\  \\  =  >  \frac{ {x}^{ \frac{11}{3} } }{4}  \\  \\  =  >   \frac{ \sqrt[3]{ {x}^{11} } }{4}

7 0
3 years ago
PLZ ANSWER WILL GIVE BRAINLIEST *NO LINKS*
Firdavs [7]

Answer:

3

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
I’m going to need you guys to come in clutch. I’m in study hall and have 21 minutes left ( I still need to finish my essay) . Yo
ipn [44]

Step-by-step explanation:

For the given figure PQRS:

Given:

PS\perp SQ    

RQ\perp QS

PQ\cong RS

To prove

\triangle PSQ\cong \triangle RQS

In Δ PSQ and ΔRQS

PS\perp SQ                             [Given]

\angle PSQ=90\°                     [Definition of perpendicular lines]

\triangle PSQ is a right triangle      [Definition of right triangles]

RQ\perp QS                             [Given]

\angle RQS=90\°                     [Definition of perpendicular lines]

\triangle RQS is a right triangle      [Definition of right triangles]

PQ\cong RS                   [Given hypotenuse of both triangles congruent]

SQ\cong QS     [ By reflexive property of congruence side QS

                              congruent to itself ]

\triangle PSQ\cong \triangle RQS     [H.L. congruence postulate]

Thus triangles are are congruent by Hypotenuse Leg postulate.

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3 years ago
URGENT!! ILL GIVE<br> BRAINLIEST!!!! AND 100 POINTS!!!!
Harlamova29_29 [7]

Answer:

To find the perimeter of the triangle, you would add p + m + n. To find the area of the triangle you would use (p x m) /2. To find a missing side of the triangle, given that it is a right triangle, you would use p^2 + m^2 = n^2

6 0
1 year ago
Find gh if g(5,-1) and h(1,-3). write your answer in simplest radical form.
Yanka [14]
Sa6a6s3
as6da
6sda6s2cx
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