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Viktor [21]
3 years ago
14

Balance the following reaction: CH4 + O2→ CO2 + H2O 46 points

Chemistry
2 answers:
lana [24]3 years ago
6 0
CH4 + 2 O2 —> CO2 + 2 H2O
Olin [163]3 years ago
3 0

Answer:

CH4 + 2 O2 —> CO2 + 2 H2O

Explanation:

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Define an Arrhenius base and describe properties of bases. Use an example to explain how an Arrhenius base will behave in water.
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An Arrhenius base is a molecule that when dissolved in water will break down to yield an OH^-or hydroxide ion in solution.

<h3>What is Arrhenius base?</h3>

An Arrhenius base is a compound that increases the OH^- ion concentration in aqueous solution.

An Arrhenius base is a substance that, when dissolved in an aqueous solution, increases the concentration of hydroxide, or , OH^- ions in the solution.

Bases Properties

Arrhenius bases that are soluble in water can conduct electricity.

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An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons. In other words, it increases the number of H^+ ions in the water. In contrast, an Arrhenius base dissociates in water to form hydroxide ions OH^-.

Example, sodium hydroxide, is added to an aqueous solution. NaOH dissociates into sodium, Na^+, and hydroxide, OH^- ions.

Learn more about the Arrhenius bases here:

https://brainly.in/question/8273595

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8 0
1 year ago
What volume of chlorine gas at 27 °C, 812 mmHg, is required to react with an excess of carbon disulfide so that 5.00kJ of heat i
Kamila [148]

Answer:

The correct answer is 1.21 L.

Explanation:

Based on the given information, the reaction will be,

CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)

By using the standard values of the substances, the standard enthalpy of the reaction is,

ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol

= -285.3 kJ/mol

The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.

Now the number of moles of chlorine needed to react to produce 5.00 kJ is,

= 5.00 kJ × 3 mol Cl2/285.3 kJ

= 0.0526 mol Cl2

Now the volume of chlorine gas at 27degree C and 812 mmHg will be,

Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm

= 1.21 L

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