Balance the following reaction: CH4 + O2→ CO2 + H2O<br> 46 points

1 Point

AleksandrR [38]

Answer:

Explanation:

A or B

I would say B do

4 0

3 years ago

Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc

wolverine [178]

Answer:

(1) 2Al(s) + 2NaOH(aq) + 6H2O(l) ↔2Na[Al(OH)4](aq) + 3H2(g)

∴ Kc = ( PH2³ * [Na[Al(OH)4]² ) / [NaOH]² = 11

(2) H2O(l) + SO3(g) ↔ H2SO4(aq)

∴ Kc = [ H2SO4 ] / PSO3 = 0.0123

(3) 2P4(s) + 6O2(g) ↔ 2P4O6(s)

∴ Kc = Kc = 1 / PO2∧6

Explanation:

(1) 2Al(s) + 2NaOH(aq) + 6H2O(l) ↔ 2Na[Al(OH)4](aq) + 3H2(g)

∴ O / Al: 0 → +2 ≡ 2e-

Na: +1 → +2

∴ R / H: +1 → 0

2 - Al - 2

2 - Na - 1

8 - O - 8

14 - H - 14

⇒ Kc = ( PH2³ * [Na[Al(OH)4]² ) / [NaOH]² = 11

(2) H2O(l) + SO3(g) ↔ H2SO4(aq)

1 - S - 1

4 - O - 4

2 - H - 2

⇒ Kc = [ H2SO4 ] / PSO3 = 0.0123

(3) 2P4(s) + 6O2(g) ↔ 2P4O6(s)

8 - P - 8

12 - O - 12

⇒ Kc = 1 / PO2∧6

6 0

3 years ago

Find ΔG° for the reactions in Problem 20.51 using ΔHf° and S° values.

pashok25 [27]

The value of ΔG° (gibbs free energy change)of the given reaction is -1131.94kj .

Given ,

Balanced chemical equation is given by,

2Mg(s) + O2 (g) → 2MgO (s)

Here , the standard enthalpy of Mg and O2 gas are zero because they are in the most stable state .

thus , the value of ΔG°rxn is given by ,

ΔG°rxn = ΔG°(products ) - ΔG°(reactants )

ΔG°rxn = [2×(-565.97 )] - 0

ΔG°rxn = 2×(-565.97)

ΔG°rxn = -1131.94kj

Hence , the value of ΔG° of the given reaction is -1131.94kj .

<h3>What is a balance chemical reaction ?</h3>

A balanced chemical reaction is a type of reaction which include the reactants and products in same amount i.e. the no of mole on both side of the reaction is remains same or balanced .

Learn more about chemical reaction here :

brainly.com/question/1893305

#SPJ4

Disclaimer :

incomplete question . here is the complete question .

Question :

Calculate ΔG° for the reaction using ΔG°f values :

2Mg(s) + O2 (g) → 2MgO (s)

Find the ΔG° for the reaction using ΔH°f and S° values .

3 0

2 years ago

According to the following reaction, how many grams of potassium sulfate will be formed upon the complete reaction of 23.8 grams

Alexxandr [17]

<u>Answer:</u> The mass of potassium sulfate that can be produced is 73.88 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

<u>For KOH:</u>

Given mass of KOH = 23.8 g

Molar mass of KOH = 56.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol$

The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:

$KHSO_4+KOH\rightarrow K_2SO_4+H_2O$

As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.

KOH is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of KOH produces 1 mole of potassium sulfate

So, 0.424 moles of KOH will produce = $\frac{1}{1}\times 0.424=0.424moles$ of potassium sulfate

Now, calculating the mass of potassium sulfate from equation 1, we get:

Molar mass of potassium sulfate = 174.26 g/mol

Moles of potassium sulfate = 0.424 moles

Putting values in equation 1, we get:

$0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g$

Hence, the mass of potassium sulfate that can be produced is 73.88 grams

8 0

3 years ago

Which type of flame(s) produce(s) incomplete combustion? Complete combustion?

Monica [59]

Answer:

See the answer and explanation below, please.

Explanation:

There are 2 types of combustion:

-Complete: C02 (carbon dioxide) is generated and the flame is blue, in the presence of a large amount of oxygen.

-Incomplete: it is also generated as a product C0 (carbon monoxide) harmful to health, and the color of the flame is yellow. It is produced in the presence of a small amount of oxygen.

8 0

3 years ago

Balance the following reaction: CH4 + O2→ CO2 + H2O 46 points