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kifflom [539]
3 years ago
6

What is the boiling point of a 0.75-molal solution of a non-volatile non-electrolyte solute in water? Kb for water = 0.52 degree

s C/ molal.
99.61 °C
100.0 °C
100.39 °C
101.44 °C
Chemistry
2 answers:
Tom [10]3 years ago
4 0
The answer is C. I just did this assignment
AVprozaik [17]3 years ago
3 0
Take the molality and multiply it by the Kb
0.75 × 0.52 = 0.39 C

then add the boiling pt to the 0.39
100 + 0.39 = 100.39 C
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<span>Answer: HgNO₃
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<span>Explanation:
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<span>In this case you are given the molecular formula Hg₂(NO₃)₂. Since, the ratio of the atoms of Hg, N, and O is 2: 2: 6, respectively, the same ratio is expressed if you divide by the greatest common factor (GCF).
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