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3 years ago

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What is the boiling point of a 0.75-molal solution of a non-volatile non-electrolyte solute in water? Kb for water = 0.52 degree

s C/ molal.
99.61 °C
100.0 °C
100.39 °C
101.44 °C

2 answers:

Tom [10]3 years ago

4 0

The answer is C. I just did this assignment

AVprozaik [17]3 years ago

3 0

Take the molality and multiply it by the Kb
0.75 × 0.52 = 0.39 C

then add the boiling pt to the 0.39
100 + 0.39 = 100.39 C

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<h3>Further explanation</h3>

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