I Believe it is 80% but I am not sure
The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
To solve an equation for a variable, you must isolate the variable on either side of the equation. To do this, simply subtract 32 from both sides of the original equation:
F ( – 32 ) = C + 32 ( – 32 )
F – 32 = C
We have proven that C is equal to (F – 32). This equation (bold) is the answer to your problem.
I hope this helps!
Answer:
28 will be your answer!
Step-by-step explanation:
I don't properly know how to explain thia but i know its the answer
