Answer:
Explanation:
Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.
For faster car on the road,
v = 2v
..........(1)
For the slower car on the road,
............(2)
Equation (1) becomes,
So, the frictional force required to keep the slower car on the road without skidding is one fourth of the faster car.
Answer:
The value is 
Explanation:
From the question we are told that
The length of the wire is 
The current density is 
The conductivity is 
Generally conductivity is mathematically represented as
Here R is the resistance which is mathematically represented as
Here I is the current which is mathematically represented as
So
And
=> 
=> 
=> 
=>
Answer:
i = 0.3326 L
Explanation:
A fixed string at both ends presents a phenomenon of standing waves, two waves with the same frequency that are added together. The expression to describe these waves is
2 L = n λ n = 1, 2, 3…
The first harmonic or leather for n = 1
Wave speed is related to wavelength and frequency
v = λ f
λ = v / f
Let's replace in the first equation
2 L = 1 (v / f₁)
For the shortest length L = L-l
2 (L- l) = 1 (v / f₂)
These two equations form our equation system, let's eliminate v
v = 2L f₁
v = 2 (L-l) f₂
2L f₁ = 2 (L-l) f₂
L- l = L f₁ / f₂
l = L - L f₁ / f₂
l = L (1- f₁ / f₂)
.
Let's calculate
l / L = (1- 309/463)
i / L = 0.3326
Refer to the diagram shown below.
i = the current in the circuit., A
R₁ = the internal resistance of the battery, Ω
R₂ = the resistance of the 60 W load, Ω
Because the resistance across the battery is 8.5 V instead of 9.0 V, therefore
(R₁ )(i A) = 9 - 8.5 = (0.5 V)
R₁*i = 0.5 (10
Also,
R₂*i = 9.5 (2)
Because the power dissipated by R₂ is 60 W, therefore
i²R₂ = 60
From (2), obtain
i*9.5 = 60
i = 6.3158 A
From (1), obtain
6.3158*R₁ = 0.5
R₁ = 0.5/6.3158 = 0.0792 Ω = 0.08 Ω (nearest hundredth)
Answer: 0.08 Ω
