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Strike441 [17]
3 years ago
6

A 2.0-kg silverware drawer does not slide readily. The owner gradually pulls with more and more force, and when the applied forc

e reaches 9.0 N, the drawer suddenly opens, throwing all the utensils to the floor. What is the coefficient of static friction between the drawer and the cabinet?
Physics
1 answer:
topjm [15]3 years ago
7 0

Answer: 0.45

Explanation:

First note that the body that causes the body to move is its moving force (Fm) which is 9.0N

Since the mass of the body is 2.0kg, the weight will be;

W= mg = 2×10

W= 20N

For static body, the frictional force (Ff) acting on the body is equal to the moving force (Fm) since both forces acts along the horizontal on the body.

Ff = Fm = 9.0N

The normal reaction (R) on the body will also be equal to its weight(W) since weight acts downwards and the reaction acts in the opposite direction (upwards).

R = W = 20N

Ff = nR taking 'n' as coefficient of static friction between the drawer and the cabinet.

9.0 = 20n

n = 9/20

n = 0.45

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Help me<br> please <br> lol<br> ?????
myrzilka [38]

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Explanation:

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3 years ago
A quantum system has three states, with energies 0, 1.6 × 10-21, and 1.6 × 10-21, in Joules. It is coupled to an environment wit
xenn [34]

To develop the problem it is necessary to apply two concepts, the first is related to the calculation of average data and the second is the Boltzmann distribution.

Boltzmann distribution is a probability distribution or probability measure that gives the probability that a system will be in a certain state as a function of that state's energy and the temperature of the system. It is given by

z = \sum\limit_i e^{-\frac{\epsilon_i}{K_0T}}

Where,

\epsilon_i = energy of that state

k = Boltzmann's constant

T = Temperature

With our values we have that

T= 250K

k = 1.381*10^{23} m^2 kg s^{-2} K^{-1}

\epsilon_1=0J

\epsilon_2=1.6*10^{-21}J

\epsilon_3=1.6*10^{-21}J

To make the calculations easier we can assume that the temperature and Boltzmann constant can be summarized as

\beta = \frac{1}{kT}

\beta = \frac{1}{(1.381*10^{23} m^2)(250)}

\beta = 2.9*10^{20}J

Therefore the average energy would be,

\bar{\epsilon} =\frac{\sum \epsilon_i e^{-\beta \epsilon_i}}{\sum e^{-\beta \epsilon_i}}

Replacing with our values we have

\bar{\epsilon} = \frac{0e^{-0}+1.6*10^{-21}*e^{-\Beta(1.6*10^{-21})}+1.6*10^{-2-1}*e^{-(2.9*10^{20})(1.6*10^{-21})}}{1+2e^{-2.9*10^{20}*1.6*10^{-21}}}

\bar{\epsilon} = 0.9*10^{-22}J

Therefore the average internal energy is \bar{\epsilon} = 0.9*10^{-22}J

3 0
3 years ago
A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute. How much power is needed for the
slavikrds [6]

A passenger weighing 500N is inside an elevator weighing 24500 N that rises 30 m every minute is 12500 W (12.5 kW).

What is Power?

Power is the amount of work that is done per unit of time. It can be associated with the speed of a change of energy within a system, or the time it takes to perform a job.

There are different types of power,

Mechanical power: is that work performed by an individual or a machine in a certain period of time.

Electric power: which is the result of the multiplication of the potential difference between the ends of a load and the current flowing there.

P= W/t

Where, P- Power,

W- Work

T- Time

The total weight of the passenger + elevator is

Fg = 500+24500

    = 25000

The total work done to rise the elevator + passenger is equal to the product between the total weight and the distance covered during the trip (d = 30 m):

W = Fgd

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The power needed for the trip is equal to the ratio between the work done (W) and the time taken (t):

P = W/t

Since the time taken is t = 1 min = 60 s, the power needed is

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Thus, Power was calculated as P = 12.5 kW.

Learn more about Power,

brainly.com/question/13357691

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