How can you increase the torque you are putting on a lever, without exerting any more force?

Physics

1 answer:

Mariana [72]3 years ago

4 0

Answer:

See below

Explanation:

Torgue = f * distance basically ...so if you want to increase torque with same f then the distance ( lever arm) must be increased

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When a mass is placed on a spring with a spring constant of 15 newtons per meter, the spring is compressed 0.25 meter. How much

Andre45 [30]

Answer:

0.47 J

Explanation:

The elastic potential energy of a spring is given as,

E = 1/2ke²........................ Equation 1

Where E = Elastic potential energy, k = spring constant, e = extension/compression.

Given: k = 15 N/m, e = 0.25 m.

Substitute into equation 1.

E = 1/2(15)(0.25)²

E = 0.46875

E ≈ 0.47 J.

Hence the elastic potential energy stored in the spring = 0.47 J

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4 years ago

Explain why mess extinctions occur and why it make sense to measure geologic time between mass extinctions

Nastasia [14]

Mass extinction occur from natural disasters, such as a n asteroid hitting earth or a volcano errupting and spread ash everywhere.

It makes sense to measure geologic time between mass extinctions because after each mass extinction, there is almost no life left and the few left have to repopulate, which may lead way to new mutations and new varieties of plants and animals.
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3 years ago

Light rays in a material with index of refrection 1.29 1.29 can undergo total internal reflection when they strike the interface

deff fn [24]

Answer:

The second material's index of refraction is 1.17.

Explanation:

Given that,

Refractive index of the material, n = 1.29

Critical angle is 65.9 degrees.

We need to find the second material's index of refraction. We know that at critical angle of incidence, angle of refraction is equal to 90 degrees. Using Snell's law as:

$n_1\sin \theta_c=n_2\sin (90)\\\\n_2=n_1\sin \theta_c\\\\n_2=1.29\times \sin (65.9)\\\\n_2=1.17$